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2 years ago

The mass of an object is 1,000 g. It has a volume of 100 mL. What is the density of the object? D= mass/volume

Chemistry

1 answer:

maxonik [38]2 years ago

4 0

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

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when you decrease the distance between two magnets that are repelling, you increase the magnetic force. True or false?

kupik [55]

Answer:

False that would be crazy but cool

3 0

2 years ago

Read 2 more answers

The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air

IceJOKER [234]

Answer:

$1.75\cdot 10^{-4} M$

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

$S = k_H p^o$

Where $k_H$ is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

$S_1 = 2.67\cdot 10^{-4} M$

Also, at sea level, we have an atmospheric pressure of:

$p = 1.00 atm$

Given mole fraction:

$\chi_{O_2} = 0.209$

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

$p^o = \chi_{O_2} p$

Then the equation becomes:

$S_1 = k_H \chi_{O_2} p$

Solve for $k_H$ :

$k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm$

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

$p = 0.657 atm$

Apply Henry's law using the constant we found:

$S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M$

8 0

3 years ago

Does apple juice have acid

stepladder [879]

Yes, it has many natural acids. However, the biggest and most prominent acid is the organic acid, malic acid.

8 0

3 years ago

Calculate the number of molecules present in 0.5 mole of water

Aleksandr-060686 [28]

Explanation:

Mole = 0.5 = n/NA

n = no. of molecule

NA = avogadro number = 6.023x 10^23

N/NA = 0.5

N = 0.5 x 6.023 x 10^23

N = 3.0115 x 10^23

6 0

2 years ago

What is osmotic pressure of a solution that contains 13.7 g of propyl alcohol (C3H7OH) dissolved in enough water to make 500 mL

azamat

Answer:

Π = iMRT ½

Explanation:

111 g

= 0.033 mol

0.033 mol CaCl2

0.09632 kg solvent

= 0.0344 m

13.7 g x 1 mol C3H7OH

60.10 g

0.5 L

(0.0821 L.atm/K.mol) (300.15K

4 0

3 years ago