Question

find three consecutive integers such that the sum of twice he smallest and 3 times the largest is 126.

Answer 1

$a,a+1,a+2\ \ -\ three\ consecutive\ integers\\\\ 2a+3(a+2)=126\\\\ 2a+3a+6=126\\\\ 5a+6=126\ \ \ |Subtract\ 6\\\\ 5a=120\ \ \ |Divide\ by\ 5\\\\ a=24\\\\Numbers\ are:\ 24,25,26.$