3 years ago

find three consecutive integers such that the sum of twice he smallest and 3 times the largest is 126.

1 answer:

vladimir1956 [14]3 years ago

8 0

$a,a+1,a+2\ \ -\ three\ consecutive\ integers\\\\
2a+3(a+2)=126\\\\
2a+3a+6=126\\\\
5a+6=126\ \ \ |Subtract\ 6\\\\
5a=120\ \ \ |Divide\ by\ 5\\\\
a=24\\\\Numbers\ are:\ 24,25,26.$

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