Answer:
Left, Left, Right, Left, Right, Right
Explanation:
Follow that order!
Answer:
Explanation:
Boyle's law states that at constant temperature:
P
PV = constant
Where: P is the pressure of a given mass of gas, and V is its volume.
The bubble wrap has a confined volume of air at constant temperature. Since a gas is easily compressible, the volume of the gas in the wrap decreases with increasing pressure. This implies that there is an inverse proportion relation between the pressure on and volume of the air.
The bubble wrap pops when stepped onto or squeezed because the pressure is high and the volume can not be compressed further. Thus, the elastic limit of the seal is exceeded. This leads to an escape of the confined air.
Answer:
The enthalpy change during the reaction is -7020.09 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.
where,
q = heat gained = ?
c = specific heat =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
The heat gained by water present in calorimeter. = q'
where,
q' = heat gained = ?
m = mass of water =
c' = specific heat of water =
= final temperature =
= initial temperature =
q ' = 12,060.38 J
Now we have to calculate the enthalpy change during the reaction.
where,
= enthalpy change = ?
Q = heat gained = -(q+q') = -(2,485.25 J + 12,060.38 J)= -14,545.63 J
Q = -14.54563 kJ
n = number of moles fructose =
Therefore, the enthalpy change during the reaction is -7020.09 kJ/mole.