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steposvetlana [31]
4 years ago
13

Theoretically, a student performing a lab experiment was expected to get 9 g of product. Instead, the student obtained only 7.8

g. What is the percent yield of the reaction performed by the student?
Chemistry
1 answer:
vichka [17]4 years ago
7 0
We are given with a theoretical amount of 9 grams of product but the student only got 7.8 grams. To calculate the percent yield, we divide the experimental amount by the theoretical amount. In this case, we divide 7.8 grams by 9 grams and multiply by 100 percent. The answer is equal to 86.67 percent.
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A 34.53 ml sample of a solution of sulfuric acid, h2s04, reacts with 27.86 ml of 0.08964 m naoh solution. calculate the molarity
Gnoma [55]
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol 
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol 
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol 
molarity of H₂SO₄ is 0.03617 M
6 0
3 years ago
Which application of hydrates best relies on the anhydrous compound’s ability to both absorb water and retain water?
anzhelika [568]
Answer : Option A) Diaper.

The main component in manufacturing of diaper is natural fibre or man made fibre both mixed, which acts as an absorber and storer of water. There are also better variations available in market which induces the more absorption and storage of fluids by using certain hydrates along with the fibres. 
3 0
3 years ago
Read 2 more answers
 
Katyanochek1 [597]

Answer:

The answer to your question is     V2 = 4.97 l

Explanation:

Data

Volume 1 = V1 = 4.40 L                    Volume 2 =

Temperature 1 = T1 = 19°C               Temperature 2 = T2 = 37°C

Pressure 1 = P1 = 783 mmHg           Pressure 2 = 735 mmHg

Process

1.- Convert temperature to °K

T1 = 19 + 273 = 292°K

T2 = 37 + 273 = 310°K

2.- Use the combined gas law to solve this problem

                  P1V1/T1  = P2V2/T2

-Solve for V2

                  V2 = P1V1T2 / T1P2

-Substitution

                  V2 = (783 x 4.40 x 310) / (292 x 735)

-Simplification

                 V2 = 1068012 / 214620

-Result

                 V2 = 4.97 l

6 0
3 years ago
A student would like to determine how heating a liquid changes its volume. The student hypothesizes that the liquid will increas
Zigmanuir [339]

Answer:

The volume of the liquid should be measured before it is heated.

Explanation:

3 0
3 years ago
What is the mass of 564 liters of oxygen in kilograms?
Alika [10]
One kg of oxygen is 0.3977 liters so:

6 0
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