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steposvetlana [31]
4 years ago
13

Theoretically, a student performing a lab experiment was expected to get 9 g of product. Instead, the student obtained only 7.8

g. What is the percent yield of the reaction performed by the student?
Chemistry
1 answer:
vichka [17]4 years ago
7 0
We are given with a theoretical amount of 9 grams of product but the student only got 7.8 grams. To calculate the percent yield, we divide the experimental amount by the theoretical amount. In this case, we divide 7.8 grams by 9 grams and multiply by 100 percent. The answer is equal to 86.67 percent.
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From the reaction: B2H6 + O2 HBO2 + H2O a. What mass of O2 will be needed to burn 36.1 g of B2H6? b. How many moles of water are
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A. The mass of O₂ needed to burn 36.1 g of B₂H₆ is 123.77 g

B. The number of mole of water, H₂O produced from 19.2 g of B₂H₆ is 1.372 mole

<h3>Balanced equation </h3>

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

Molar mass of B₂H₆ = (2×11) + (1×6) = 28 g/mol

Mass of B₂H₆ from the balanced equation = 1 × 28 = 28 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 3 × 32 = 96 g

SUMMARY

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

<h3>A. How to determine the mass of O₂ needed </h3>

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

Therefore

36.1 g of B₂H₆ will require = (36.1 × 96) / 28 = 123.77 g of O₂

Thus, 123.77 g of O₂ is required for the reaction

<h3>B. How to determine the mole of water produced </h3>

We'll begin by calculating the number of mole of in 19.2 g of B₂H₆. This can be obtained as follow:

  • Mass of B₂H₆ = 19.2 g
  • Molar mass of B₂H₆ = 28 g/mol
  • Mole of B₂H₆ =?

Mole = mass / molar mass

Mole of B₂H₆ = 19.2 / 28

Mole of B₂H₆ = 0.686 mole

Finally, we shall determine the number of mole of water produced. This is illustrated below:

<h3>Balanced equation </h3>

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

From the balanced equation above

1 mole of B₂H₆ reacted to produce 2 moles of H₂O

Therefore, H₂O

0.686 mole of B₂H₆ will react to produce = 0.686 × 2 = 1.372 mole of H₂O

Thus, 1.372 mole of H₂O was obtained from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

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two drops of mercury on a flat surface are rolled towards each other. When they make contact with each other they fuse to form o
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