Answer:
The percentage is k 
%
Explanation:
From the question we are told that
The mass of the stibnite is 
The volume of KBrO3(aq) is 
The concentration of KBrO3(aq) is 
Now the balanced ionic equation for this reaction is
The number of moles of 
is
substituting values
from the reaction we see that 1 mole of reacts with 3 moles of 
so 0.003325 moles will react with x moles of
Therefore
Now the molar mass of is a constant with a values of 
Generally the mass of is mathematically represented as
substituting values
The percentage of Sb(antimony) in the overall mass of the stibnite is mathematically evaluated as
k 
k %
Answer:
2 KCIO₃ → 2 KCI + 3 O₂
Explanation:
A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.
You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.
However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.
The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.
2 KCIO₃ → KCI + 3 O₂
<u>Reactants</u>
K --- 2
C--- 2
I --- 2
O --- 6
<u>Products</u>
K --- 1
C --- 1
I --- 1
O --- 6
Notice that number of K, C and I atoms on the left-hand side of the equation has also changed.
2 KCIO₃ → 2 KCI + 3 O₂
<u>Reactants</u>
K --- 2
C --- 2
I --- 2
O --- 6
<u>Products</u>
K --- 2
C --- 2
I --- 2
O --- 6
The equation is now balanced.
Explanation:
5.76 is the answer
vinegar a day and the molarity of the vinegar is 0.84 M, then how m
Answer:
0.128 g
Explanation:
Given data:
Volume of gas = 146.7 cm³
Pressure of gas = 106.5 Kpa
Temperature of gas = 167°C
Mass of oxygen gas = ?
Solution:
Volume of gas = 146.7 cm³ (146.7 /1000 = 0.1467 L)
Pressure of gas = 106.5 Kpa (106.5/101 = 1.1 atm)
Temperature of gas = 167°C (167 +273.15 = 440.15 K)
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1.1 atm× 0.1467 L / 0.0821 atm.L/ mol.K × 440.15 K
n = 0.1614 / 36.14 /mol
n = 0.004 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.004 mol × 32 g/mol
Mass = 0.128 g
