The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.
- Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.
F = G (M₁M₂)/r²
Where, F the gravitational force
G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant
M₁=5.98×10²⁴kg mass of earth
M₂= 1.99×10³⁰ kg the mass of the sun
r =15×10¹⁰ m is the distance between sun and earth
Putting all the values in above equation,
F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m
On solving the above equation we get,
F = 3.48×10²²N
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Answer:
a) The number density is 3.623 × 10⁻³ 
The mass of the atmosphere is 1.3 × 10²²Kg
b) The pressure is 10⁻²⁰ Millimeter of mercury
c) The mass mixing ratio is 0.0107
The partial pressure of ethane is 0.01114 Pa
Yes it is condensable because it boiling point is -88.5 C which is equivalent to 184.5 K i.e is adding 273 to -88.5C and the temperature of the atmosphere is 37 K.
Explanation:
The explanation is on the first and second uploaded image
Answer:
his acceleration rate is -0.00186 m/s²
Explanation:
Given;
initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)
time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s
final position of the car, x₁ = 150 miles = 241,350 m
time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s
The initial velocity is calculated as;
u = 160, 900 m / 3,600 s
u = 44.694 m/s
The final velocity is calculated as;
v = 241,350 m / 6,000 s
v = 40.225 m/s
The acceleration is calculated as;

Therefore, his acceleration rate is -0.00186 m/s²
Answer:

Explanation:
Given:
- thickness of the base of the kettle,

- radius of the base of the kettle,

- temperature of the top surface of the kettle base,

- rate of heat transfer through the kettle to boil water,

- We have the latent heat vaporization of water,

- and thermal conductivity of aluminium,

<u>So, the heat rate:</u>


<u>From the Fourier's law of conduction we have:</u>


where:
area of the surface through which conduction occurs
temperature of the bottom surface

is the temperature of the bottom of the base surface of the kettle.