2 years ago

What are the classes of alkanol

Chemistry

1 answer:

LuckyWell [14K]2 years ago

8 0

1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL

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To prepare an acetic acid/acetate buffer, a technician mixes 30.6 mL of 0.0880 acetic acid and 21.6 mL of 0.110 sodium acetate i

enyata [817]

Answer: There are 0.00269 moles of acetic acid in buffer.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of acetic acid solution = 0.0880 M

Volume of solution = 30.6 mL

Putting values in equation 1, we get:

$0.0880M=\frac{\text{Moles of acetic acid}\times 1000}{30.6ml}\\\\\text{Moles of acetic acid}=\frac{0.0880\times 30.6}{1000}=0.00269mol$

Thus there are 0.00269 moles of acetic acid in buffer.

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2 years ago

n one type of solar energy system, sunlight heats the air within solar panels, which heats copper tubes filled with water. What

Ratling [72]

I believe it is D as you are hearing the copper tube

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2 years ago

Order the elements from smallest to largest atomic number

postnew [5]

the largest is francium, Z=87 , or caesium, Z=55 ; and the smallest is definitely helium, Z=2 .

Explanation:

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2 years ago

17 points Pls helpppppopppp

pentagon [3]

Answer:

Lipids

Explanation:

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2 years ago

"You measure 48.9 mL of a solution of sulfuric acid with an unknown concentration, and carefully titrate this solution using a 1

Blizzard [7]

Answer:

C= 0.532M

Explanation:

The equation of reaction is

H2SO4 + 2KOH = K2SO4+ H2O

nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml

Applying

CAVA/CBVB = nA/nB

(CA× 48.9)/(1.5×34.7)= 1/2

Simplify

CA= 0.532M

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2 years ago