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Leni [432]
3 years ago
10

31) To extend a length of 1.00 inches, 2.54 x 10^8 average sized atoms would have to be placed in a straight line (in other word

s, 2.54 x 10^8 atoms per 1.00 inches) how many average sized atoms, placed in a straight line, would be required to
form a line extending from the Earth to the moon when the moon is its farthest distance from the
Earth? When the earth and moon are as far apart from each other as they ever get, the distance between the two is 405,696 km
Chemistry
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

Here's the conversion factor you need:

1 Kilometer   =   39370 inches

So, for your question we want to go 405,696 km....

405696 km   x   39370 inches/ 1 km  =   15972283464 inches

                       

15972283464 inches   x   2.54 x10^8 atoms/1 inch   =   4.05 x 10^18 atoms

                                     

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Which of the following has more atoms?
aniked [119]

Answer:

They all have the same number of atoms

Explanation:

Which of the following has more atoms?

One mole of zinc

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O They all have the same number of atomst

a mole of anything contains Avogadros number of 6.022X10^23  things

which has the greatest number of thing? a dozen eggs, a dozen cookies, a dozen pizzas?

a dozen is a number means 12

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3 0
3 years ago
Which of these processes are chemical reactions?
masya89 [10]
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8 0
3 years ago
Why the bonds between nonmentals tend to be covalent
natita [175]
Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.
7 0
3 years ago
What is the average atomic mass of chlorine if the mass of one isotope is 34.97 amu and has a p?er cent abundance of 75.77%. The
pishuonlain [190]

Answer : The average atomic mass of chlorine is, 32.37 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

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Percentage abundance of isotope 1 = 75.77 %

Fractional abundance of isotope 1 = 0.7577

Mass of isotope 2 = 36.97 amu

Percentage abundance of isotope 2 = 24.23 %

Fractional abundance of isotope 2 = 0.2423

Now put all the given values in above formula, we get:

\text{Average atomic mass of element}=\sum[(34.97\times 0.7577)+(24.23\times 0.2423)]

\text{Average atomic mass of element}=32.37amu

Therefore, the average atomic mass of chlorine is, 32.37 amu

8 0
3 years ago
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