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1 year ago

Why a hole at the bottom of a ship is more dangerous than the one that is near the surface?

Physics

1 answer:

Korolek [52]1 year ago

8 0

Answer:

Because due to hole water accumulated in the ship in the bottom must point causes shifting of gravitational point upward so their chance of sinking of <u>ship.</u>

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A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the positive +z-direction. The magnetic field is unif

marysya [2.9K]

The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:

In Cartesian form F = 2.46 i ^ - 0.605 j ^

In the form of magnitude and direction F = 2.53 N and θ = 346.2º

Given parameters.

Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.

The current i = 9.00 A in the positive direction of the z axis.

The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T

To find.

Magnetic force.

The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.

F = i L x B

Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.

The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.

$F= i |L| \left[\begin{array}{ccc}i&j&k\\L_x&L_y&L_z\\B_x&B_y&B_z\end{array}\right]$

Let's calculate.

$F= 9.00 \ 0.25 \ \left[\begin{array}{ccc}i&j&k\\0&0&1\\-0.242&-0.985&-0.336\end{array}\right]$

$F = 2.26 \ ( - 1 B_y i \ + 1 B_x j \ )$

F = 2.5 (0.985 i ^ - 0.242 j ^)

F = ( 2.46 i ^ - 0.605 j^ ) N

To find the magnitude we use the Pythagorean theorem.

F = $\sqrt{F_x^2 + F_y^2}$

F = $\sqrt{2.46^2 + 0.605^2}$

F = 2.53 N

Let's use trigonometry for the direction.

Tan θ ’= $\frac{F_y}{F_x}$

θ'= tan⁻¹ $\frac{F_y}{F_x}$

θ'= tan⁻¹1 ( $\frac{-.605}{2.46}$ )

θ’= -13.8º

To measure this angle from the positive side of the x-axis counterclockwise.

θ = 360- θ'

θ = 360 - 13.8

θ = 346.2º

In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:

In Cartesian form F = 2.46 i ^ - 0.605 j ^

In the form of magnitude and direction F = 2.53 N and θ = 346.2º

Learn more here: brainly.com/question/2630590

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2 years ago

an object with a mass of 70kilograms is supported at a height 8meters above the ground. what's the potential energy of the objec

ra1l [238]

Gravitational Potential Energy = mgh (m=mass; g=gravitational force(9.8N/kg); h = height)

Ug = (70kg)(9.8N/kg)(8m) = 5488J which is C.)

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3 years ago

Marus traveled on a motorcylce distance of 1,298meters north to get to the nearest shopping center. He then turned back south an

andrew-mc [135]

Answer:

48 meters north

Explanation:

If you measure the distance between the point Marus started and the point where they stopped after traveling 1,250 meters back south, you get 48 meters. To make this a displacement quantity, you add 'north' to the end and get 48 meters north, considering this was the initial direction of the motorcycle.

6 0

3 years ago

A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a

lions [1.4K]

Answer:

Approximately $4.61\times 10^{3}\; {\rm N}$ upwards (assuming that $g = 9.81\; {\rm m\cdot s^{-2}}$ .)

Explanation:

External forces on this astronaut:

Weight (gravitational attraction) from the earth (downwards,) and
Normal force from the floor (upwards.)

Let $(\text{normal force})$ denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

$\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ .

Let $m$ denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be $(\text{weight}) = m\, g$ .

Let $a$ denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be $(\text{net force}) = m\, a$ .

Rearrange $\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ to obtain an expression for the magnitude of the normal force on this astronaut:

$\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}$ .

3 0

1 year ago

GIVING BRAINLIST!!!!

34kurt

A negative object so it takes in the charged object and nothing will happen until something else would touch it I think

3 0

2 years ago

Read 2 more answers

Why a hole at the bottom of a ship is more dangerous than the one that is near the surface?​

Why a hole at the bottom of a ship is more dangerous than the one that is near the surface?