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professor190 [17]
3 years ago
12

Which is the correct scientific notation for 724,000,000,000?

Physics
1 answer:
NikAS [45]3 years ago
5 0

Answer:

Explanation:

scientific notation for 724,000,000,000 is

7.24*10^11

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Light incident on a surface at an angle of 45° undergoes diffused reflection at what angle will it reflect?
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Answer:

Option (D)

Explanation:

Reflection is the phenomenon in which a ray of light strikes on a smooth and polished surface and then bounce back into the same medium at same angle.

There are two types of reflection.

1. Regular reflection or specular reflection

2. Irregular reflection or diffused reflection

When a parallel beam of light falls on a smooth and highly polished surface and after reflection the rays are also parallel to each other, it is called regular reflection.

When after parallel beam of light falls on a rough surface and after reflection the rays of light goes in random directions, it is called diffused reflection.

The rays reflected at 90 degree to - 90 degree in diffused refectory.

5 0
3 years ago
In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80m/
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V o - initial velocity
v = velocity at the maximum height,
v² = v o² - 2 g h
v = 0
0 = v o² - 2 g h
v o² = 2 g h = 2 · 9.80 · 0.460
v o² = 9.052
v o = √9.052 = 3.004197 m/s ≈ 3 m/s
8 0
3 years ago
Samuel adds a teaspoon of salt to a glass of water. He notices that the salt disappears. Samuel takes a dip to discover that the
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It is a chemical change because the salt is dissolving.
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A 1.0-cm-diameter pipe widens to 2.0, then narrows to 0.5. Liquid flows through the first segment at a speed of 4.0. What is the
uysha [10]

Answer:

3.14 ×  10⁻⁴  m³  /s

Explanation:

The flow rate (Q) of a fluid is passing through different cross-sections remains of pipe always remains the same.

Q = Area x velocity

Given:

Diameters of 3 sections of the pipe are given as  

d1  =  1.0  cm,  d2  =  2.0  cm  and  d3  =  0.5  cm.

Speed in the first segment of the pipe is  

v1  =  4  m/s.

From the equation of continuity the flow rate through different cross-sections remains the same.

Flow  rate  =  Q  =  A1  v1  =  A2  v2  =  A3  v3.

Q = A1v1

   =π/4  d²1  v1  =  π/4  * 0.01² ×4.0 m³/s  =  3.14 ×  10⁻⁴  m³  /s

3 0
3 years ago
Review Conceptual Example 6 as background for this problem. A car is traveling to the left, which is the negative direction. The
DiKsa [7]

Answer:

(a) 1.21 m/s² (b) 1.75 m/s²

Explanation:

The initial speed of the car, u = 17.8 m/s

Case 1.

Final speed of the car, v = 23.5 m/s

Time, t = 4.68-s

Acceleration = rate of change of velocity

a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2

Case 2.

Final speed of the car, v = 15.3 m/s

a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2

Hence, this is the required solution.

3 0
3 years ago
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