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2 years ago

Which of the following is a vector quantity?

Physics

1 answer:

djverab [1.8K]2 years ago

4 0

Vector quantity is defined by direction as well as magnitude both

so now lets discuss all option

1) distance = it is total path length between two points so there is no direction needed in it so it is scalar

2) Speed = it is ratio of total distance covered and total time, so it also do not require any direction.

<em>3)velocity = it is ratio of displacement and time, and displacement is always given with direction so velocity is a vector quantity</em>

4) time = time is the measurement of the interval of two events and we do not require any direction in it so its a scalar quantity.

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Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and

mart [117]

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

$\lambda=\frac{v}{f}$

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

$f=288 Hz$

$v=1.45\cdot 10^3 m/s$

Substituting into the equation, we find the wavelength:

$\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m$

3 0

3 years ago

I don't get the flat line on a graph. on a distance/speed or motion graph, they say it is not moving. that is what I don't get i

timofeeve [1]

A flat line means the the speed is the same . Its moving at the same pace.

4 0

3 years ago

A roller coaster car is elevated to a height of 30 m and released from rest to roll along a track. At a certain time T it is at

Naddika [18.5K]

Explanation:

Initial energy = final energy + work done by friction

PE = PE + KE + W

mgH = mgh + 1/2 mv² + W

(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v² + 25000

v = 22.1 m/s

Without friction:

PE = PE + KE

mgH = mgh + 1/2 mv²

(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v²

v = 23.4 m/s

4 0

2 years ago

A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The

Alex787 [66]

Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

$\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2$

$Kx^2=mv^2$

$v=\sqrt{\dfrac{kx^2}{m}}$

By putting the values

$v=\sqrt{\dfrac{kx^2}{m}}$

$v=\sqrt{\dfrac{1300\times 0.264^2}{25}}$

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

$V_f^2=V_i^2-2gh$

By putting the values

$0^2=1.9^2-2\times 10\times h$

h=0.1805 m

h=18.05 cm

4 0

3 years ago

How would you describe a fossil that was discovered in a rock at the base of a cliff to a fossil in a rock found at the top of a

ArbitrLikvidat [17]

The one at the base would be much older due to the law of super position, and the rock at the top would be much newer,again, due to the law of super position.

7 0

2 years ago