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3 years ago

Does a neutrally charged object even have a charge?

2 answers:

8 0

“Charged objects have an imbalance of charge - either more negative electrons than positive protons or vice versa. And neutral objects have a balance of charge - equal numbers of protons and electrons. The principle stated earlier for atoms can be applied to objects. Objects with more electrons than protons are charged negatively; objects with fewer electrons than protons are charged positively.

In this discussion of electrically charged versus electrically neutral objects, the neutron has been neglected. Neutrons, being electrically neutral play no role in this unit. Their presence (or absence) will have no direct bearing upon whether an object is charged or uncharged. Their role in the atom is merely to provide stability to the nucleus.”

Hope this helps a bit.

!! (Credits to The Psychics Classroom) !!

Bas_tet [7]3 years ago

5 0

Neutral objects have a balance of charge - equal numbers of protons and electrons. ... Their presence (or absence) will have no direct bearing upon whether
an object is charged or uncharged.

I hope this would be helpful

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Which of the following happens to an object in uniform circular motion?

podryga [215]

Answer:

As an object moves in a circle, it is constantly changing its direction. ... Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed.

5 0

4 years ago

A charge +q is located at the origin, while an identical charge is located on the x axis at x = +0.57 m. A third charge of +2q i

Jlenok [28]

Answer:

The third charge placed is 0.80 m.

Explanation:

Given that,

Distance = 0.57 m

First charge = q

Third charge = 2q

We need to calculate the electrostatic force on charge q₁ due to q₂

Using formula of electrostatic force

$F_{21}=\dfrac{kq_{1}q_{2}}{r_{1}^2}$

When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is

$F_{net}=F_{21}+F_{31}$

The net electrostatic force on the charge at the origin doubles.

$2F_{21}=F_{21}+F_{31}$

$F_{31}=F_{21}$

$\dfrac{kq_{3}q_{1}}{r_{2}^2}=\dfrac{kq_{2}q_{1}}{r_{1}^2}$

$\dfrac{q_{3}}{r_{2}^2}=\dfrac{q_{2}}{r_{1}^2}$

$r_{2}^2=\dfrac{q_{3}}{q_{2}\timesr_{1}^2}$

$r_{2}=\sqrt{\dfrac{q_{3}}{q_{2}}}r_{1}$

Put the value into the formula

$r_{2}=\sqrt{\dfrac{2q}{q}}\times0.57$

$r_{2}=\sqrt{2}\times0.57$

$r_{2}=0.80\ m$

Hence, The third charge placed is 0.80 m from origin in x-axis.

4 0

3 years ago

Pls help me this is being timed. pls.

ahrayia [7]

Answer:

10N each

Explanation:

Doing a little math here to make it balanced. 10+10=20 therefore you have the same on both sides.

Hope this helps!

6 0

3 years ago

Tyler has learned that potential energy is energy stored. Tyler's teacher asks the students to come up with a demonstration of p

Advocard [28]

D.A child at the top of a slide

7 0

4 years ago

Read 2 more answers

A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res

Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy $E_k = \frac{mv^2}{2}$ where m is bullet mass, v is the velocity

Formula for work $W = FS$ where F is the average force and S is the distance travelled.

$E_k = W$

$\frac{mv^2}{2} = FS$

$F = \frac{mv^2}{2S}$

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

$F = \frac{0.0042*370^2}{2*1.2} = 239.575 N$

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

$a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)$

We also have $v(t) = v_0 + at$

At the time the bullet is coming to rest, $v(t) = 0, a = -57041.67 m/s^2$

Therefore, $0 = 370 - 57041.67t$

$t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms$

3 0

4 years ago