How is work related to force and displacement?
1 answer:
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Answer:
0.42 m/s²
Explanation:
r = radius of the flywheel = 0.300 m
w₀ = initial angular speed = 0 rad/s
w = final angular speed = ?
θ = angular displacement = 60 deg = 1.05 rad
α = angular acceleration = 0.6 rad/s²
Using the equation
w² = w₀² + 2 α θ
w² = 0² + 2 (0.6) (1.05)
w = 1.12 rad/s
Tangential acceleration is given as
= r α = (0.300) (0.6) = 0.18 m/s²
Radial acceleration is given as
= r w² = (0.300) (1.12)² = 0.38 m/s²
Magnitude of resultant acceleration is given as
= 0.42 m/s²
Answer:
Energy stored, E = 0.072 J
Explanation:
Given that,
Capacitance,
Capacitance,
These two capacitor are connected in parallel, and charged to a potential difference of, V = 60 volts
We know that in parallel combination of capacitor, the equivalent capacitance is given by :
The energy stored in the capacitor is given by :
So, the energy stored in the capacitor in this capacitor combination is 0.072 J.