Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature in Kelvins
K = equilibrium constant
We have :
1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)
The free energy change for the reaction at 37.0°C is -8.741 kJ.
6.2 divided by the mass number of NO3 is 0.1 moles. Anytime your trying to find the moles of something you divide it by the mass number of your combined elements.
Warmer objects have faster particles and higher temperatures. If two objects have the same mass, the object with the higher temperature has greater thermal energy. Temperature is measured with a thermometer.
<u>Answer:</u> The value of 
for the chemical equation is 
<u>Explanation:</u>
For the given chemical equation:
To calculate the for given value of Gibbs free energy, we use the relation:
where,
= Gibbs free energy = 78 kJ/mol = 78000 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant =
T = temperature = 1000 K
= equilibrium constant in terms of partial pressure = ?
Putting values in above equation, we get:
Hence, the value of for the chemical equation is
<span>Rubidium and cesium have similar chemical properties because in the ground state the atoms of both elements each have one electron in the outermost shell. The correct option is A. The two elements belong to group one of the periodic table; all elements in this group have only one electron in their outmost shell which they easily give away to other elements during chemical reactions in order to attain octet structure.</span>
