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Dvinal [7]
3 years ago
14

Describe what happens, at a microscopic level, when an object is charged by rubbing. For instance, what happens when a plastic p

ipe is rubbed with a cloth? Describe the specific case where the rod becomes negatively charged
Physics
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

Explanation:

The static charges are generated due to excess or deficiency of electrons, because these are the smallest quanta of charge available at the molecular level which can get transferred with minimal energy requirement.

These charges are usually generated by friction between  the two surfaces leading to the transfer of electron from one to another.

When a plastic pipe is rubbed with a cloth then due to friction the surface of the cloth loses electron which gets stuck at the surface of the pipe making it negatively charged.

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A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A bloc
Nikitich [7]

Answer:

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

Explanation:

From the law of conservation of energy

Energy lost  by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr

0.5kd^{2}=0.5mv^{2}+mgLsin\theta+\mu_{k}mgcos\theta x

x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

The required distance from A to B is x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

5 0
3 years ago
A charge moves a distance of 1.8 cm in the direction of a uniform electric field having a magnitude of 214 N/C. The electrical p
Andrei [34K]

Answer:

 13.4 x 10 raise to power -19  C

Explanation:

. The distance moved by a charge in the direction of a uniform electric field is d= 1.8 cm =0.018 m

. The uniform electric field is  E = 214 N/M

, The decrease in electrical potential energy is   d(P.E) = 51.63 x 10 raise to power -19 J

Let the magnitude of the charge of the moving particle be q

which is given by the equation

d(P.E) =qEd

51.63 x 10 power -19 = q(214)(0.018)

51.63 x 10 power -19 =3.852q

by making q the formular,

q = 13.4 x 10 power -19 C  

5 0
3 years ago
What instrument is used to expand burr holes?
k0ka [10]
Craniotomes are used
4 0
3 years ago
A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.
jeka57 [31]

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

  • The body is gaining the speed, which means there is a change in kinetic energy.
  • The change in kinetic energy is equal to the work done.
  • The friction force is the product of coefficient of the friction and normal force.
  • The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

7 0
1 year ago
Read 2 more answers
An airplane refuels in Bakersfield and continues on to Fresno. It travels an average speed of 610 km/h. IF the trip takes 2.75 h
rusak2 [61]

2.75x610km

1220+7.5x61

1220+427 ... just over

1647

8 0
2 years ago
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