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notsponge [240]
3 years ago
5

What is the peak emf generated (in V) by rotating a 1000 turn, 42.0 cm diameter coil in the Earth's 5.00 ✕ 10−5 T magnetic field

, given the plane of the coil is originally perpendicular to the Earth's field and is rotated to be parallel to the field in 12.0 ms?
Physics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

5.77 Volt

Explanation:

N = 1000, Diameter = 42 cm = 0.42 m,  t = 12 ms = 12 x 10^-3 s

Change in magnetic field, B = 5 x 10^-5 T

The peak value of emf is given by

e = N x dФ / dt

e = N x A x dB/dt

e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)

e = 5.77 Volt

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Explanation:

v = d \div t \\ v = 35m \div 40sec = 0.875 \: m \: per \: sec

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8 0
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A body moves in a straight line. At time, it's acceleration is given by a = 12t + 1. When t =0, the velocity of the body v is 2
madreJ [45]

Answer:

v = 6t² + t + 2, s = 2t³ + ½ t² + 2t

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Explanation:

a = 12t + 1

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s = ∫ v dt

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At t = 0, s = 0.

0 = 2(0)³ + ½ (0)² + 2(0) + C

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At t = 3:

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5 0
3 years ago
9. A constant velocity means acceleration is
vampirchik [111]

Answer:

d. zero

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hope this helps you

have a good day :)

6 0
2 years ago
A car is 200 m from a stop sign and traveling toward the sign at 40.0 m/s. At this time, the driver suddenly realizes that she m
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Answer:

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Answer:

My answer :

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sea-level change

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