What is the peak emf generated (in V) by rotating a 1000 turn, 42.0 cm diameter coil in the Earth's 5.00 ✕ 10−5 T magnetic field , given the plane of the coil is originally perpendicular to the Earth's field and is rotated to be parallel to the field in 12.0 ms?
1 answer:
Answer:
5.77 Volt
Explanation:
N = 1000, Diameter = 42 cm = 0.42 m, t = 12 ms = 12 x 10^-3 s
Change in magnetic field, B = 5 x 10^-5 T
The peak value of emf is given by
e = N x dФ / dt
e = N x A x dB/dt
e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)
e = 5.77 Volt
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