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gregori [183]
3 years ago
9

A satellite dish is shaped like a paraboloid of revolution. The signals that emanate from a satellite strike the surface of the

dish and are reflected to a single​ point, where the receiver is located. If the dish is 12 feet across at its opening and 2 feet deep at its​ center, at what position should the receiver be​ placed?
Physics
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

18feet

Explanation:

We need to find the distance,c between the vertex and the focus.

For a vertical parabola:

y=\frac{0.25}{c}(x-h)^2+k

#If we place our parabola at the center, the expression changes to:

y=\frac{0.25}{c}x^2

The points of the parabola are given as (12,2), substitute in our equation to find c:

y=\frac{1}{4c}x^2\\\\2=\frac{1}{4c}\times12^2\\\\c=12

Hence, the receiver should be placed at 18ft

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