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salantis [7]
3 years ago
13

A straight line is drawn on the surface of a 14-cm-radius turntable from the center to the perimeter. A bug crawls along this li

ne from the center outward as the turntable spins counterclockwise at a constant 45 rpm. Its walking speed relative to the turntable is a steady 3.8 cm/s. Let its initial heading be in the positive x-direction, where the x- and y-directions are fixed relative to the laboratory. As the bug reaches the edge of the turntable (still traveling at 3.8 cm/s radially, relative to the turntable) what are the x and y components of the velocity of the bug?
Physics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:

v = \left[\begin{array}{c}0.66&0\end{array}\right]m/s

Explanation:

The position vector r of the bug with linear velocity v and angular velocity ω in the laboratory frame is given by:

\overrightarrow{r}=vtcos(\omega t)\hat{x}+vtsin(\omega t)\hat{y}

The velocity vector v is the first derivative of the position vector r with respect to time:

\overrightarrow{v}=[vcos(\omega t)-\omega vtsin(\omega t)]\hat{x}+[vsin(\omega t)+\omega vtcos(\omega t)]\hat{y}

The given values are:

t=\frac{x}{v}=\frac{14}{3.8}=3.7 s

\omega=\frac{45\times2\pi}{60s}=4.7\frac{1}{s}

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I need help plz and thank you this is due
xeze [42]

Answer:

Grow up man, this is completely based on your curriculum, we would need your book to answer, and this has to be done by you.

3 0
3 years ago
Read 2 more answers
A plane travels 350 km south along a straight path with an average velocity of 125 km/h to the south. The plane has a 30 minute
faust18 [17]
Average Velocity = Total Displacement / Total time

1st part of journey,  350 km at velocity 125 km/h

Time = 350 / 125 = 2.8 hours.

2nd part of journey,  220 km at velocity 115 km/h

Time = 220 / 115 = 1.9 hours


Average Velocity = Total Displacement / Total time

                               = (350 + 220) / (2.8 + 1.9)

                                =   570 / 4.7  ≈ 121.3 km/hr

Average Velocity ≈ 121 km/hr due south. 

Option C. 
6 0
2 years ago
What is the difference between the initial position and the final position of an object?
Grace [21]
The initial is where you are starting and the final postion is where the object ends up
5 0
2 years ago
A capacitor is charged to a potential difference of 3 volt it delivers 30% store energy to lamp what is the final potential diff
nexus9112 [7]

Answer:

3.98V

Explanation:

Given

Pontential difference V as 3v

Energy delivered is 30%,

Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)

So E=V^2

E=3^2=9

At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3

But E=V^2

✓E=V

✓6.3=3.98V

4 0
2 years ago
A girl is floating in a freshwater lake with her head just above the water. If she weighs 610 N, what is the volume of the subme
Elden [556K]

Answer:

The volume of the submerged part of her body is 0.0622m^{3}

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

B=ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

W_{girl}=B (I)

Where ''W'' is weight

⇒ If we consider ρ = 1000\frac{kg}{m^{3}} (water density) and g=9.81\frac{m}{s^{2}} and replacing this values in the equation (I) ⇒

B=W_{girl}

B=610N

ρ.V.g = 610N

1000\frac{kg}{m^{3}}.V.(9.81\frac{m}{s^{2}})=610N (II)

The force unit ''N'' (Newton) is defined as

N=kg.\frac{m}{s^{2}}

Using this in the equation (II) :

(9810\frac{N}{m^{3}}).V =610N

V=\frac{610N}{9810\frac{N}{m^{3}}}

V=0.0622m^{3}

We find that the volume of the submerged part of her body is 0.0622m^{3}

8 0
3 years ago
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