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alexandr1967 [171]
2 years ago
13

The thermal transfer of energy by electromagnetic waves through the vacuum of space is called

Physics
2 answers:
Murrr4er [49]2 years ago
5 0

Answer:

Radiation

Explanation:

Olenka [21]2 years ago
4 0

Answer: Radiation

Explanation:

There are three ways in which the thermal transfer occurs:

   1. By Conduction, when the transmission is by the <u>direct contact</u>.

  2. By Convection, heat transfer <u>in fluids </u>(like water or the air, for example).  

   3. By Radiation, by the <u>electromagnetic waves</u> (they can travel through any medium and in <u>vacumm</u>)

So, in the outter space is vacuum, this means the energy cannot be transmitted by convection, nor conduction. It must be transmitted by electromagnetic waves that are able to travel with or without a medium, and this is called radiation.

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Does a five pound ball weigh more or less 40000 miles above sea level​
Ann [662]

It would weigh less bc the higher you are the less gravity there is.

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Two pieces of flint rock produce a visible spark
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<span>(3) electromagnetic energy and internal energy</span>
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Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e
blondinia [14]

Answer:

Explanation:

Electron's kinetic energy = 2 eV

= 2 x 1.6 x 10⁻¹⁹ J

1/2 m v² = 3.2 x 10⁻¹⁹

1/2 x 9.1 x 10⁻³¹ x v² = 3.2 x 10⁻¹⁹

v² = .703 x 10¹²

v = .8385 x 10⁶ m/s

Electrons revolve in a circular orbit when forced to travel in a magnetic field whose radius can be expressed as follows

r = mv / Bq

where m , v and q are mass , velocity and charge of electron .

here given magnetic field B = 90 mT

= 90 x 10⁻³ T

Putting these values in the expression above

r =  mv / Bq

= \frac{9\times10^{-31}\times.8385\times10^6}{90\times10^{-3}\times1.6\times10^{-19}}

= .052 mm.

3 0
3 years ago
The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -41 oC and 900 Pa, respect
Fittoniya [83]

Answer:

Part a)

\rho = 0.0205 kg/m^3

Part b)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

Explanation:

Part a)

As per ideal gas equation we know that

PM = \rho RT

here we know that Martian atmosphere is equivalent to that of carbon

so we will have

P = 900 Pa

T = 273 - 41 = 232 K

now we will have

(900)(0.044) = \rho (8.31)(232)

\rho = 0.0205 kg/m^3

Part b)

Now for the earth surface the density of air is given for

P = 101.6 kPa

T = 18 ^oC

so we will have

PM = \rho RT

(101.6\times 10^3)(0.029) = \rho(8.31)(273 + 18)

\rho = 1.22 kg/m^3

So density of atmosphere at Martian Surface is very less than the density at Earth.

8 0
2 years ago
A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
ruslelena [56]
  • T1=40°C=313K
  • T_2=-10°C=263K

Applying Charles law

\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}

\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}

\\ \sf\Rrightarrow V_2=84.02ml

6 0
2 years ago
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