A mother and daughter press their hands together and then push apart while ice skating. Immediately after they push away from ea
ch other, how does the motion of the mother and daughter change? 
2 answers:
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Answer:
(a)
(b)
(c)
Explanation:
(a) According to Newton's second law, the acceleration of a body is directly proportional to the force exerted on it and inversely proportional to it's mass.
(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:
(c) Using the kinematics equation:
For the girl, we have and
. So:
For the sled, we have . So:
When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:
Now, we solve (1) for
Answer:
60 kg m/s
Explanation:
Let be the acceleration of the object.
As the acceleration of the object is constant, so
Given that applied force, F=6.00 N,
From Newton's second law, we have
,
[from equation (i)]
[given that time, t=10 s and F=6 N]
Here mv is the final momentum of the object and mu is the initial momentum of the object.
So, the change in the momentum of the object is mv-mu.
Hence, the change in the momentum of the object is 60 kg m/s.