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Cerrena [4.2K]
2 years ago
9

A mother and daughter press their hands together and then push apart while ice skating. Immediately after they push away from ea

ch other, how does the motion of the mother and daughter change? ​

Physics
2 answers:
kherson [118]2 years ago
7 0

Answer:

J

Explanation:

The daughter moves with greater acceleration backwards because of her weight.

vova2212 [387]2 years ago
3 0

Answer:D on DCP

Explanation:

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Young’s modulus is property of gas
eduard

Explanation:

Sorry but I don't Understand question

3 0
3 years ago
Your washer has power of 450 watts, and your dryer has a power of 3000
qaws [65]

Answer:

See explanations below

Explanation:

Power = Workdone/Time

Power of washer = 450watts

Time used to clean the clothes = 1hour = 3600secs

Energy used to clean a load of clothes in 1 hour of

washing = 450/3600

Energy used to clean a load of clothes in 1 hour of

washing = 0.125Joules

For drying;

Energy = 3000/1.5*3600

Energy = 3000/5400

Energy = 0.556Joules

Hence the energy in washing id 0.556Joules

4 0
2 years ago
A wave is produced from a vibrating string on a violin. Two observers are standing 20 m and 40 m away from the musician. The obs
max2010maxim [7]

Well the one that is closer can see and hear more

3 0
3 years ago
Two thin 80.0-cm rods are oriented at right angles to each other. Each rod has one end at the origin of the coordinates, and one
kogti [31]

Answer:

The net force on the electron is given as:

F = 1.35 x 10⁻¹³ N j - 1.35 x 10⁻¹³ N i

Explanation:

Given:

charge on rod along x-axis = Q₁ = -15 x 10⁻⁶ C

charge on rod along y-axis = Q₂ = 15 x 10⁻⁶ C

distance of electron from rod 1 = r₁ = 0.4 m

distance of electron from rod 1 = r₂ = 0.4 m

charge on electron = q = -1.6 x 10⁻¹⁹ C

ε° = 8.85 x 10⁻¹² C²/Nm²

Electric force on charge due to rod 1:

F₁ = qE = 1/4πε°(qQ₁/r₁²)

F₁ = (9 x 10⁹ x -1.6 x 10⁻¹⁹ x -15 x 10⁻⁶)/0.4²

F₁ = 1.35 x 10⁻¹³ N

Negative negative repels each other so the rod will Force the electron in positive y-direction.

F₁ = 1.35 x 10⁻¹³ N j

Electric force on charge due to rod 2:

F₂ = qE = 1/4πε°(qQ₂/r₂²)

F₂ = (9 x 10⁹ x -1.6 x 10⁻¹⁹ x 15 x 10⁻⁶)/0.4²

F₂ = - 1.35 x 10⁻¹³ N

Opposite charges attract each other so the rod will force the electron in negative x-direction.

F₂ =  - 1.35 x 10⁻¹³ N i

Net Force:

F = F₁ + F₂

F = 1.35 x 10⁻¹³ N j - 1.35 x 10⁻¹³ N i

4 0
3 years ago
Por una resistencia de 10 Ω fluyen 5A. ¿Cuál será la diferencia de potencial que se le debe aplicar a la resistencia?
ra1l [238]

Answer:

V = 50 volts

Explanation:

Given that,

Resistance, R = 10 ohms

Current, I = 5 A

We need to find the potential difference across the circuit. We know that,

V = IR

Put all the values,

V = 5 × 10

V = 50 volts

Hence, the potential difference is equal to 50 volts.

8 0
3 years ago
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