1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
damaskus [11]
2 years ago
5

A saline solution similar to that used for intravenous drips is made by dissolving 0.45 g sodium chloride in 50.00 g water. Whic

h of the following statements concerning the saline solution and the law of conservation of mass is/are correct?1. The mass of the saline solution is greater than the mass of water.
2. The mass of the saline solution is equal to the combined mass of sodium chloride and water.
3. The mass of the saline solution is greater than the mass of the sodium chloride.
A) 1 only
B) 2 only
C) 3 only
D) 1 and 2
E) 1, 2, and 3
Chemistry
1 answer:
beks73 [17]2 years ago
7 0

Answer:

E) 1, 2, and 3

Explanation:

50g H2O + 0.45g NaCl --> 50.45g saline solution

You might be interested in
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
Please help me would really appreciate it thank you :)
tatyana61 [14]

Answer:

e. 8.04*10^4

Explanation:

80.4 g converted to mg is 80,400. 8.04*10^4= 80,400

4 0
2 years ago
If the lungs of a child hold 0.11 mol of air in a volume of 2.8 L, then the lungs of an average female adult, with a volume is 4
Aleks [24]

Answer:

Explanation:

A childs lung can hold .11mols/ per 2.8 L so that gives us a molarity of .039M

A adults lungs can hold .18 mols /per 4.6 so that gives us .039M aswell meaining that the lung capacity between the two is not different.

4 0
2 years ago
Consider the reaction below:
melisa1 [442]

Answer:

(A) first order reaction

Explanation:

A first order reaction is a type of reaction in which the rate of the reaction depends only on the concentration on one of the reactants. Since A is the only reactant we have, it is right to deduce that this reaction is a first order reaction.

Note: while the order of this reaction is 1, its molecularity is 2. The molecularity of a reaction is the number of moles of reactants that is actually reacting.

(B) is wrong

This is because a zero order reaction is one in which the rate of reaction is not influenced by the concentrations of the reactants and hence remains constant irrespective. Since we were not furnished with this idea in the question, it is only right that we reject this answer.

(C) is wrong.

C is outrightly wrong as we have only one reactant.

(D) is wrong

We have only one reactant.

6 0
3 years ago
When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e
sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂  

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

                2 Al(s)  +  3Cl₂(g)  ⇒   2AlCl₃

Process

a) Calculate the molar mass of the reactants  

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion  Al/Cl₂ = 53.96/212.7 = 0.254

   Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

                    53.96 g of Al ------------------ 212.7 g of Cl₂

                     40.5 g of Al -------------------  x

                      x = (40.5 x 212.7) / 53.96

                      x = 8614.35 / 53.96

                      x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

                  = 53.057 g

d) Calculate the moles of Cl

                       35.45 g of Cl ----------------- 1 mol

                       53.057 g of Cl ---------------  x

                        x = (53.057 x 1)/35.45

                       x = 1.49 mol of Cl₂                    

6 0
3 years ago
Read 2 more answers
Other questions:
  • Cells get energy from food to sustain the life of the organism.
    8·2 answers
  • We say that salts will dissociate but acids will react with water. We say that acids will
    5·1 answer
  • Which of the example most complete description an objects motion?
    13·1 answer
  • A neutral atom of sulfur has the following characteristics:
    11·1 answer
  • Which ions contribute to alkalinity
    5·1 answer
  • Mixture with two or more substances that are evenly mixed
    10·1 answer
  • Helooo i need help please :)
    12·1 answer
  • The girl I liked just asked me who I liked.
    14·2 answers
  • An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese ru
    12·1 answer
  • Select the correct answer. if two half-lives have passed since a scientist collected a 1.00-gram sample of u-235, how much u-235
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!