Answer:
A) increasing the pressure
Explanation:
Given the exothermic reaction:
2SO₂(g) + O₂(g) ↔ 2SO₃(g)
the question asks what will make the number of moles of SO₃(g) to increase.
When an equilibrium is disturbed, the system will shift in order to counteract the change (see <em>Le Chatelier's Principle</em>) So <em>when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles </em>(because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.
The number of moles in the right side is 2 and the number of moles in the left side is 3.
The final volume of the methane gas in the container is 6.67 L.
The given parameters;
- <em>initial volume of gas in the container, V₁ = 2.65 L</em>
- <em>initial number of moles of gas, n₁ = 0.12 mol</em>
- <em>additional concentration, n = 0.182 mol</em>
The total number of moles of gas in the container is calculated as follows;
The final volume of gas in the container is calculated as follows;
Thus, the final volume of the methane gas in the container is 6.67 L.
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