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Anna007 [38]
2 years ago
9

If 200 mg of HCl is added to water to achieve a final volume of 1L, what is the final pH?

Chemistry
2 answers:
Anvisha [2.4K]2 years ago
8 0

hope this helps ..................

miskamm [114]2 years ago
5 0

Answer:

The pH of the solution is 2.26 .

Explanation:

Mass of HCl = 200 mg = 0.200 g

1 mg = 0.001 g

Moles of HCl =n=\frac{0.200 g}{36.5 g/mol}=0.005479 mol

Volume of the solution ,V= 1 L

Molarity of HCl solution = \frac{n}{V}

[HCl]=\frac{0.005479 mol}{1 L}=0.005479 mol/L

1 mole of HCk gives 1 mole of hydrogen ion and 1 mole of chloride ions.

[HCl]=[H^+]=[Cl^-]=0.005479 mol/L

The pH of the solution is negative logarithm of hydrogen ion concentration:

pH=-\log[H^+]

pH=-\log[0.005479 mol/L]=2.26

The pH of the solution is 2.26 .

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Answer : The enthalpy change for the reaction is, 97.7 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main chemical reaction is,

2C(s)+3H_2O(g)\rightarrow CH_4(g)+CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)     \Delta H_1=131.3kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) CH_4(g)+H_2O(g)\rightarrow 2H_2(g)+CO(g)    \Delta H_3=206.1kJ

Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :

(1) 2C(s)+2H_2O(g)\rightarrow 2CO(g)+2H_2(g)     \Delta H_1=2\times 131.3kJ=262.6kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) 2H_2(g)+CO(g)\rightarrow CH_4(g)+H_2O(g)    \Delta H_3=-206.1kJ

The expression for enthalpy of main reaction will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

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\Delta H=97.7kJ

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Answer:

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Explanation:

We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case KCl03) in 1000ml of solution (1 liter):

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<em></em>

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