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Anna007 [38]
3 years ago
9

If 200 mg of HCl is added to water to achieve a final volume of 1L, what is the final pH?

Chemistry
2 answers:
Anvisha [2.4K]3 years ago
8 0

hope this helps ..................

miskamm [114]3 years ago
5 0

Answer:

The pH of the solution is 2.26 .

Explanation:

Mass of HCl = 200 mg = 0.200 g

1 mg = 0.001 g

Moles of HCl =n=\frac{0.200 g}{36.5 g/mol}=0.005479 mol

Volume of the solution ,V= 1 L

Molarity of HCl solution = \frac{n}{V}

[HCl]=\frac{0.005479 mol}{1 L}=0.005479 mol/L

1 mole of HCk gives 1 mole of hydrogen ion and 1 mole of chloride ions.

[HCl]=[H^+]=[Cl^-]=0.005479 mol/L

The pH of the solution is negative logarithm of hydrogen ion concentration:

pH=-\log[H^+]

pH=-\log[0.005479 mol/L]=2.26

The pH of the solution is 2.26 .

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Which is more stable: neutral chlorine atoms or chlorine ions? Why?​
lubasha [3.4K]

Answer:

When we say "chlorine wants to gain one electron", we speak of the radical atom. Chlorine as a free radical, Cl⋅ , is the chlorine atom that we say has 7 valence electrons and wants its 8th to form an octet. So, Cl⋅ , chlorine radical, is less stable, and Cl− , chlorine ion, is more stable

3 0
2 years ago
Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of
Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n .  R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

5 0
3 years ago
Read 2 more answers
No links please. How many moles of methane (CH4) are in 7.31x10^25 molecules?
ad-work [718]

Answer:

molar mass of methane CH4

= C + 4 H  

= 12.0 + 4 x 1.008

= 12.0 +  4.032

= 16.042g/mol

7.31 x 10^25 molecules x             1 mole  CH4      = 121.43 moles

                                      6.02 x 10^23 CH4 molecules

121.43 moles CH4 are present.

Explanation:

not to certain if this is right or not.. but hope it helps!

4 0
2 years ago
According to the collision theory and model created to explain the collision theory, what two factors must be satisfied for a gi
storchak [24]
The answer is correct orientation and sufficient energy. Answer choice D
4 0
3 years ago
Read 2 more answers
How many moles of HNO3 are present if 4.90×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution?
Amiraneli [1.4K]

Answer:

0.098 moles

Explanation:

Let y represent the number of moles present

1 mole of Ba(OH)₂ contains 2 moles of OH- ions.

Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.

To get the y moles, we then do cross multiplication

1 mole *  y mole = 2 moles * 0.049 mole

y mole = 2 * 0.049 / 1

y mole =  0.098 moles of OH- ions.

1 mole of OH- can neutralize 1 mole of H+

Therefore, 0.098 moles of HNO₃ are present.

3 0
3 years ago
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