Question

If 200 mg of HCl is added to water to achieve a final volume of 1L, what is the final pH?

Answer 1

hope this helps ..................

Answer 2

Answer:

The pH of the solution is 2.26 .

Explanation:

Mass of HCl = 200 mg = 0.200 g

1 mg = 0.001 g

Moles of HCl =$n=\frac{0.200 g}{36.5 g/mol}=0.005479 mol$

Volume of the solution ,V= 1 L

Molarity of HCl solution = $\frac{n}{V}$

$[HCl]=\frac{0.005479 mol}{1 L}=0.005479 mol/L$

1 mole of HCk gives 1 mole of hydrogen ion and 1 mole of chloride ions.

$[HCl]=[H^+]=[Cl^-]=0.005479 mol/L$

The pH of the solution is negative logarithm of hydrogen ion concentration:

$pH=-\log[H^+]$

$pH=-\log[0.005479 mol/L]=2.26$

The pH of the solution is 2.26 .