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RUDIKE [14]
3 years ago
10

A "fizz-keeper" is a small air pump that you can place on an opened soda bottle. When operated the pump is used to pressurize th

e air space above the soda by pumping in air from the outside. Based on Henry's law, this would be expected to __________ the solubility of carbon dioxide in the remaining soda.
Chemistry
1 answer:
AnnZ [28]3 years ago
3 0

Answer: increase

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

As soda contains carbon dioxide dissolved in water.

The equation given by Henry's law is:

C_{CO_2}=K_H\times p_{CO_2}

where,

C_{CO_2} = solubility of carbon dioxide in water

K_H = Henry's constant

p_{CO_2} = partial pressure of carbon dioxide

Thus on increasing the pressure, the solubility of carbon dioxide also increase.

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When something slows it’s acceleration is
Minchanka [31]

Answer:

negative

Explanation:

When something slows down, its acceleration is the opposite of the velocity.

8 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
A fixed mass of gass occupies a volume of 200cm at 21°c calculate it's volume at standard temperature
elena55 [62]
The answer is in the attachment below:

4 0
2 years ago
8.
Oksi-84 [34.3K]

Answer:

900 mg

Explanation:

4 0
3 years ago
Which of the following is a variable property for a gas ? Select all that apply.
disa [49]
C) volume
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The volume of gas depends on e.g. temperature and pressure.
8 0
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