Rectangle A is similar to rectangle B. Rectangle B has sides that are 4 times longer than rectangle A. What is the relationship
between the perimeters of rectangles A and B A. The perimeter of rectangle A is equal to the perimeter of rectangle B.
B. The perimeter of rectangle B is 4 times the perimeter of rectangle A.
C. The perimeter of rectangle B is 8 times the perimeter of rectangle A.
D. The perimeter of rectangle B is one-fourth the perimeter of
rectangle A.
The answer is option B. let the sides of rectangle A be x and y so the sides of rectangle B will be 4x and 4y perimeter of recyangle A= 2(l+b) =2(x+y) =2x+2y perimeter of rectangle B=2(l+b) = 2(4x+4y) =2*4(x+y) = 8 (x+y) Therefore their ratio= 8(x+y) / 2(x+y) =4/1 Therefore Perimeter of rectangle B is 4 times perimeter of rectangleA Hope I helped!