In movies about space, there is frequently a space battle scene where ships

Chemistry

1 answer:

tangare [24]3 years ago

3 0

The correct answer is C. There is no oxygen in space, so there can be no combustion.

Explanation:

Fire and flames are the result of a chemical process known as combustion. Moreover, for combustion to occur there are two essential elements. The first one is a fuel or a substance that releases energy and ignites, and the second one is an oxidant, which accepts electrons. This mix and reaction causes high temperatures and release of heat in the form of fire and flames.

This implies, that for fireballs or any other form of fire to exist there must be oxygen or any substance that replaces it. This does not occur in space because the levels of oxygen are extremely low, this means, at least oxygen is added fireballs are not possible in this context as there is no oxygen, and therefore no combustion (Option C).

You might be interested in

A molecule composed of atoms is called _________.

Readme [11.4K]

I believe that the answer is element

3 0

3 years ago

Read 2 more answers

Compare the number of moles calculated in parts a) 0.03 and b). 0.064. Which of the three possible reactions discussed is consis

Snowcat [4.5K]

Answer:don’t click link ur gonna get ur info taken

Explanation:

6 0

3 years ago

Help! Help ASAP! Using bonding principles, describe why AlCl3 forms an ionic bond

Artemon [7]

If you look at AIF3 and AICI3, the F ion is smaller than a CI ion. that’s why AICI3 will make a covalent bond while AIF3 will make a ionic bond. explanation: AICI3 doesn’t have a complete transfer of electrons between the metal and the non-metal.

4 0

2 years ago

2.0 mol of gas occupy 44.8 l at a temperature of 0°c. what is the pressure of the gas

MArishka [77]

The pressure of the gas is 1.0 bar.

pV = nRT

T = (0 + 273.15) K = 273.15 K

p = (nRT)/V = (2.0 mol × 0.083 14 bar·L·K⁻¹mol⁻¹ × 273.15 K)/44.8 L = 1.0 bar

5 0

3 years ago

In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?

IRINA_888 [86]

$2 C_{6}H_{6} + 15O_{2} ----->\ \textgreater \ 12CO_{2} + 6H_{2}O


$

$mol of benzene = \frac{mass}{Mr}$
= $\frac{10.47g}{(6 * 12) (6 * 1) g/mol}$
= 0.134 mol

mol of oxygen:
ratio of $C_{6} H_{6} : O_{2}$
= 2 : 15
= 1 : 7.5

: . mol of $O_{2}$ = 0.134mol * 7.5
= 1.01 mol

Mass of Oxygen = mol * Mr
= 1.01 mol * (16*2) g/mol
= 32.22g

Note: Mr is molar mass

8 0

3 years ago