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Luda [366]
3 years ago
7

Write an importance of endothermic reactions​

Chemistry
1 answer:
KengaRu [80]3 years ago
8 0

Answer:

the uses of exothermic reactions are:

1) lighting of stove

2) self heating cans

3) hand warmers

4) in some case exothermic process can be used to cook food such as rice  (by adding calcium oxide to water heat is evolved and it helps to cook food )

Explanation:

hope this helps you pls mark me as brainilst

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A wave has 9.2 x 10-22 ) of energy. What is its wavelength?
blagie [28]

Answer:

\lambda=2.2x10^{-4}m

Explanation:

Hello!

In this case, since the relationship between energy and wavelength is defined via the speed of light and the Planck's constant as shown below:

e=\frac{c*h}{\lambda}

Since c stands for the speed of light and h for the so-called Planck's constant, we can compute the wavelength as follows:

\lambda=\frac{c*h}{e}=\frac{3.0x10^8m/s*6.626x10^{-34}J*s}{9.2x10^{-22}J}\\\\\lambda=2.2x10^{-4}m

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3 0
3 years ago
The force that one massive object exerts to attract another object is called .
Ghella [55]

Answer:

Gravity

Explanation:

The force that one massive object exerts to attract another object is called gravity.

4 0
2 years ago
Read 2 more answers
A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
Over [174]
In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0
3 years ago
The International Date Line
geniusboy [140]

Answer:

The International Date Line, established in 1884, passes through the mid-Pacific Ocean and roughly follows a 180 degrees longitude north-south line on the Earth. It is located halfway round the world from the prime meridian—the zero degrees longitude established in Greenwich, England, in 1852.

8 0
2 years ago
Chlorine can bond with fluorine to form CIF. Chlorine can also bond with lithium to form LiCI Which compound will have a greater
Sergio [31]

Answer: ClF will have a greater partial charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a low difference of electronegativities between the atoms, thus resulting in charge difference. Example: ClF

Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms and thus there is no charge difference. Example: F_2

Ionic bond is formed when there is complete transfer of electron from a highly electropositive metal to a highly electronegative non metal. The electronegative difference between the elements is high. The charges on cation and anion neutralise each other. Example: LiCl

Thus as ClF will have greater partial charge.

5 0
3 years ago
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