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zysi [14]
3 years ago
8

Will chlorine gas effuse more quickly than ammonia gas

Chemistry
2 answers:
beks73 [17]3 years ago
6 0
This statement is false due to the fact that the ammonia gas has the lower molar mass.
SVEN [57.7K]3 years ago
6 0
No ammonia has lower molar mass . So this is not true
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An aqueous solution of 1.29 M ethanol, CH3CH2OH, has a density of 0.988 g/mL. The percent by mass of CH3CH2OH in the solution is
anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g

Now, the mass of the ethanol:

m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g

Finally, the by mass percent is:

m/m=\frac{59.34g}{988g}*100\\%

%m=6%

Best regards.

4 0
3 years ago
A LA TEMPERATURA DE 35°C, UNA MUESTRA DE DIOXIDO DE CARBONO OCUPA UN VOLUMEN DE 350 ML. ¿Qué CAMBIO DE VOLUMEN SE PRODUCIRA SI L
Kisachek [45]

Answer:

New volume = 150 mL

Explanation:

Initial temperature, T₁ = 35°C

Initial volume, V₁ = 350 mL

We need to find the change in volume when the temperature drops to 15°C.

The relation between the temperature and the volume is given by Charle's law. Let new volume is V₂. It can be given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{350\times 15}{35}\\\\V_2=150\ mL

So, the new volume is 150 mL.

8 0
3 years ago
Help me please for brainliest and 10 points.
Stella [2.4K]

Answer:

The red arrow from igneous to sedimentary rock

Explanation:

When rocks are weathered and eroded, they become sediment. This sediment is later compacted and cemented to form sedimentary rock. Therefore, the red arrow going from igneous rock to sedimentary rock represents weathering and erosion.

7 0
3 years ago
According to VSEPR Theory, the molecular geometry for CH3+ is
Ne4ueva [31]
I think it’s C but anybody can correct me if I’m wrong
3 0
2 years ago
How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol
mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

2Al + 3Cu{(NO_3)}_2  \rightarrow 2Al{(NO_3)}_3 +3 Cu

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

Al \rightarrow Al^{3+} + 3e^-

And copper goes from +2 to 0

Cu^{2+} + 2e^-\rightarrow Cu

On balancing the number of electrons we get:

For 1 mole of Al 6e^- is required.

Therefore for 2 moles of Al,

Total (2\times6)F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

brainly.com/question/27985929

#SPJ4

4 0
1 year ago
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