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Olin [163]
3 years ago
10

A cylinder with a radius of 5.6 cm and a height of 10.7 cm has what volume? (You can look up the formula for the volume of a cyl

ind er and pi's value.)
Chemistry
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

V=1054.2cm^{3}

Explanation:

1. First take the cylinder volume formula:

V=\pi.r^{2}.h

2. Then take the values for the radius and the height of the cylinder and replace them into the formula:

V=\pi*(5.6cm)^{2}*(10.7cm)

3. Solve the equation:

V=\pi*(31.36cm^{2})*(10.7cm)

V=\pi*335.5cm^{3}

V=1054.2cm^{3}

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Explanation:

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I hope this helps!

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1 year ago
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1. Take a look at all the elements in period 3. What do you notice? *
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Which element is least likely to react with other elements
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3 years ago
If you added 15,000 calories to 2.0 L of water that was at 25.0 degrees C, what temperature would it be at when you finished?
rewona [7]

<u>Answer:</u>

<em>When we finish, the temperature would be 32.5℃</em>

<em></em>

<u>Explanation:</u>

Density of water = mass/volume

So,

Mass of water = Density × Volume

\\\\$=1.0   \times  2.0 L$\\\\$=1.0 \frac{g}{m L} \times 2000 m L$\\\\$\quad=2000 g$

$Q=m \times c \times \Delta T$

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

plugging in the values  

$15000 \mathrm{Cal}=2000 \mathrm{g} \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times \Delta T$

\\$\Delta T=\frac{15000 \mathrm{cal}}{2000 \mathrm{g} \times \frac{1.0 \mathrm{cal}}{g^{\circ} \mathrm{C}}}$\\\\$\Delta T=7.5^{\circ} \mathrm{C}$

Final T = ∆T + Initial T

= 7.5℃ + 25℃ = 32.5℃ (Answer).

5 0
2 years ago
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