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3 years ago

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What are flavonoids responsible ?

1 answer:

Radda [10]3 years ago

8 0

Answer: Flavonoids are a diverse group of phytonutrients (plant chemicals) found in almost all fruits and vegetables. Along with carotenoids, they are responsible for the vivid colors in fruits and vegetables. ... Like other phytonutrients, flavonoids are powerful antioxidants with anti-inflammatory and immune system benefits.

Explanation:

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The speed of an aircraft is measure in the unit_

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Read 2 more answers

Point PP is a distance d1d1 = 4.0 mm above a large sheet of metal that carries a current of 35 AA in the positive xx direction a

zhenek [66]

Answer:

The width of the sheet is $w =0.8046m$

Explanation:

From the question we are told that

The distance of point P above a large sheet of metal is $D = 4.0mm =\frac{4}{1000} = 0.004m$

The current on the large metal sheet is $I =34A$

The distance of the the point P below a long wire $d = 3.0mm = \frac{3}{1000} = 0.003m$

The current on the long wire is $I_w = 0.41A$

The magnetic field at P is $B = 0T$

Generally magnetic field of P long wire is mathematically represented as

$B_w = \frac{\mu_o I_w}{2\pi r}$

Generally magnetic field of P large sheet of meta is mathematically represented as

$B_m = \frac{\mu_o K}{2}$

Where K is the current per unit width

The total magnetic field at P is

$\frac{\mu_o I_w}{2 \pi r} = \frac{\mu_o K}{2}$

Making K the subject of formula

$K = \frac{2 I_w }{2 \pi r }$

Substituting values

$K = \frac{2 * 0.41 }{2 * 3.142 * (0.0030) }$

$K = 43.4967 A/m$

Generally K is mathematically represented as

$K = \frac{I}{w}$

Where w is the width of the large sheet

Therefore the width of the metal sheet $w = \frac{I}{K}$

$= \frac{35}{43.4967}$

$w =0.8046m$

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2 years ago

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Explanation:

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