<span>H(t) = -16t^2 + vt + s
</span><span>Part A:
</span>Using the given data:
H(t)= -16*t² + 60*t + 82;
Part B:
Put H(t)=0
0<span>= -16*t² + 60*t + 82;</span>
Use the quadratic formula to find t.
See the attachment...'t' is replaced with 'x'.
 
        
        
        
Answer:
D). 
Explanation:
As we know that temperature scale is linear so we will have

now we have

so the relation between two scales is given as

now we know that in kelvin scale the absolute temperature is 600 K
so now we have

so correct answer is
D). 
 
        
             
        
        
        
Answer:
Explanation:
- given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s
- acceleration = 0.032 X 2 /(1.30×10−8)^2
a = 3.79 x 10^14m/s^2
E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19
E = magnitude of this electric field. = 2156.3N/C
b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as
= 2 X 3.79 x 10^14 X 0.032
= 4.92 X 10^6m/s
 
        
             
        
        
        
Answer:
The value is  
 
Explanation:
From the question we are told that 
 The distance of friends house from your point is 
 The distance of your friends street from your street is 
 The diagram illustrating this question is shown on the first uploaded image 
 From the diagram we can apply by Pythagoras theorem as follows 
 
=>      
 
=>      
 
=>      
 
 
        
             
        
        
        
One of Kepler's laws is that the orbits of planets are elliptical. It's not a suggestion.
BTW, circles are ellipses too, but so special that their likelihood is close to zero.