Find and irrational number between 7.7 and 7.9

1 answer:

7 0

An irrational number is a number that can't be written as a rational number

to undestnad that, I will define what a rational number is
a rational number is a number that can be written in the form a/b where b≠0
repeating decimals are not irrational because the repeat can be made into a fraction, example: 0.1111111111=1/9

some common irrational numbers are pi or e or √2

a cheat way to make an irrational number between 7.6 and 7.7 would be this
I will make in terms of pi because the expanded form will be infinite since pi has infinite digits

find the bounds
I will do pi times c=that number
find teh bounds of c
7.6/pi≈2.419
7.9/pi≈2.514
so a number between 2.419 and 2.514 is 2.5, a nice number

so we can say that 2.5π is an irrational number between 7.6 and 7.9 (it evaluates to about 7.8539816339744830961566084581988....

You might be interested in

Quick TIMED does anyone know this algebra 2 question? Will give brainiest

USPshnik [31]

I think it is the third one

7 0

3 years ago

Read 2 more answers

Lost as usual yep I am

denpristay [2]

Answer:

y = -3x -4

Step-by-step explanation:

A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.

The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.

The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...

3(x+3) +(y-5) = 0

This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:

3x +9 +y -5 = 0 . . . . . eliminate parentheses

y = -3x -4 . . . . . subtract terms that are not "y"