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Tomtit [17]
2 years ago
7

A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What

is the magnitude of the centripetal acceleration of the car as it goes around the curve?
Physics
1 answer:
Vikentia [17]2 years ago
4 0

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

a_{c} =\frac{v^{2} }{r}

Where a_{c} is the centripetal acceleration

v is the velocity

and r is the radius

From the given information

v = 12 \ m/s

and r = 30 \ m

Therefore,

a_{c} =\frac{12^{2} }{30}

a_{c} =\frac{144 }{30}

a_{c} = 4.8\ m/s^{2}

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

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A 1380 kg car starts from rest at the
Ulleksa [173]

Answer: 72200

Explanation:

First you must find the height for this is on an inclined hill using:

h=Lsin(angle) —> 28.0sin(11.0) = 5.34

Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.

Using mgh:

m=1380

g=9.80

h=5.34

(1380)(9.8)(5.34)

=72218.16

*Rounding to the 3rd=72200

Hope this helps :)

6 0
2 years ago
Laser transmissions travel at a higher speed than the radio waves true or false
uranmaximum [27]
<span>False. Laser transmissions and radio waves are both forms of electromagnetic radiation. Both travel at approximately 3.00 x 10^8 meters per second. This is the case because wavelength and frequency are directly proportional to this value. Although laser light has a shorter wavelength than radio waves, it will travel at the same speed because the frequency will be greater.</span>
6 0
3 years ago
Dr. Glover's office has one vendor for their practice management software and another for their electronic health record, but th
Sliva [168]

Answer:

Interface

Explanation:

This is a classic example of Interface technology.

An interface allows different software packages to communicate without re-entering data.

Here in this case also systems are able to communicate with one another without duplicating data entry. For example, practice management software and another for their electronic health record.

5 0
3 years ago
if a car is traveling at an average speed of 60 kilometers per hour, how long does it take to travel 12 kilometers?
VashaNatasha [74]
Im sure its twelve minutes
5 0
3 years ago
Recall from Chapter 1 that a watt is a unit of en- ergy per unit time, and one watt (W) is equal to one joule per second ( J·s–1
harkovskaia [24]

Answer:

Explanation:

The energy of a photon is given by the equation E_p=h f, where h is the <em>Planck constant</em> and f the frequency of the photon. Thus, N photons of frequency f will give an energy of E_N=N h f.

We also know that frequency and wavelength are related by f=\frac{c}{\lambda}, so we have E_N=\frac{N h c}{\lambda}, where c is the <em>speed of light</em>.

We will want the number of photons, so we can write

N=\frac{\lambda E_N}{h c}

We need to know then how much energy do we have to calculate N. The equation of power is P=E/t, so for the power we have and considering 1 second we can calculate the total energy, and then only consider the 4% of it which will produce light, or better said, the N photons, which means it will be E_N.

Putting this paragraph in equations:

E_N=(\frac{4}{100})E=0.04Pt=(0.04)(100W)(1s)=4J.

And then we can substitute everything in our equation for number of photons, in S.I. and getting the values of constants from tables:

N=\frac{\lambda E_N}{h c}=\frac{(520 \times10^{-9}m) (4J)}{(6.626\times10^{-34}Js) (299792458m/s)}=1.047 \times10^{19}

3 0
3 years ago
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