Explanation:
Atoms of some elements shows no desire to form bonds or combine with themselves or other kinds of atom because their outer energy levels are completely filled.
Helium has a duplet configuration whereas other atoms of the noble gases have an octet configuration.
- The driving force for many interatomic bonding is the tendency to have completely filled outer energy levels like the noble gases.
- The various interatomic bonds form in a bid of the atom to be isoelectronic in the outer energy level with the noble gases.
- This leads to loss, gain or sharing of electrons between atoms.
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Answer:
The induced emf for this silver circle during this period of expansion is 0.0314 V.
Explanation:
Given that,
Initial radius = 0.075 m
Magnetic field = 1.5 T
Radius = 0.125 m
Time t =1.5 s
We need to calculate the induced emf for this silver circle
Using formula of emf
Put the value ino the formula
Hence, The induced emf for this silver circle during this period of expansion is 0.0314 V.
Answer:
Kinetic to potential energy.
Explanation:
A rock sinks through water at a constant speed is a type of kinetic to potential energy conversion. The rock movement refers to kinetic energy whereas sinking in the water represents potential energy due to movement from top to bottom in the water. So we can say that the kinetic to potential energy conversion is occurring in this example.
Answer:
The lowest possible frequency of sound for which this is possible is 1307.69 Hz
Explanation:
From the question, Abby is standing 5.00m in front of one of the speakers, perpendicular to the line joining the speakers.
First, we will determine his distance from the second speaker using the Pythagorean theorem
l₂ = √(2.00²+5.00²)
l₂ = √4+25
l₂ = √29
l₂ = 5.39 m
Hence, the path difference is
ΔL = l₂ - l₁
ΔL = 5.39 m - 5.00 m
ΔL = 0.39 m
From the formula for destructive interference
ΔL = (n+1/2)λ
where n is any integer and λ is the wavelength
n = 1 in this case, the lowest possible frequency corresponds to the largest wavelength, which corresponds to the smallest value of n.
Then,
0.39 = (1+ 1/2)λ
0.39 = (3/2)λ
0.39 = 1.5λ
∴ λ = 0.39/1.5
λ = 0.26 m
From
v = fλ
f = v/λ
f = 340 / 0.26
f = 1307.69 Hz
Hence, the lowest possible frequency of sound for which this is possible is 1307.69 Hz.
The formula for impulse is F*(t₂-t₁)=m*(v₂-v₁), where F is the force, t is time, m is mass and v is velocity.
In our case m*(v₂-v₁)=16 N s, m=4 kg, v₁=0 and t₁=0.
m*(v₂-0)=16 N s, we solve for v₂:
4*v₂= 16
v₂=16/4
v₂=4 m/s
So the final velocity of the ball is v₂=4 m/s.