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3 years ago

Le Châtelier's principle tells us that chemical _____ will adjust in an attempt to remove a stressor.

1 answer:

8 0

Le Châtelier's principle tells us that chemical c. equilibrium will adjust in an attempt to remove a stressor.

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A. Choose one of the four biogeochemical cycles that were discussed in this unit - carbon, nitrogen, water, or oxygen and descri

MAVERICK [17]

Water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

<h3>What is are the stages of water cycle?</h3>

These are the basic stages through which water passes. These stages are:

Evaporation
Condensation
Precipitation
Collection.

So therefore, water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

Learn more about water cycle:

brainly.com/question/25796102

#SPJ1

6 0

2 years ago

(a) Write the balanced neutralization reaction that occurs between H2SO4 and KOH in aqueous solution. Phases are optional. (b) S

Sunny_sXe [5.5K]

These are two questions and two answers

Answer:

Question 1:

H₂SO₄ (aq) + 2KOH (aq) → K₂SO₄ (aq) + 2H₂O (l)

Question 2:

0.201 M

Explanation:

Question 1:

The neutralization reaction that occurs between H₂SO₄ and KOH is an acid-base reaction.

The products of an acid-base reaction are salt and water.

This is the sketch of such neutralization reaction:

1) Word equation:

sulfuric acid + potassium hydroxide → potassium sulfate + water

↑ ↑ ↑ ↑

acid base salt water

2) Skeleton equation (unbalanced)

H₂SO₄ + KOH → K₂SO₄ + H₂O

#) Balanced chemical equation (including phases)

H₂SO₄ (aq) + 2KOH (aq) → K₂SO₄ (aq) + 2H₂O (l) ← answer

Question 2:

1) Mol ratio:

Using the stoichiometric coefficients of the balanced chemical equation you get the mol ratio:

1 mol H₂SO₄ (aq) : 2 mol KOH (aq) : 1 mol K₂SO₄ (aq) : mol 2H₂O (l)

2) Moles of H₂SO₄:

V = 0.750 liter
M = 0.480 mol/liter
M = n/V ⇒ n = M×V = 0.480 mol/liter × 0.750 liter = 0.360 mol

3) Moles of KOH:

V = 0.700 liter
M = 0.290 mol/liter
M = n/V ⇒ n = M × V = 0.290 mol/liter × 0.700 liter = 0.203 mol

4) Determine the limiting reagent:

a) Stoichiometric ratio:

1 mol H₂SO₄ / 2 mol NaOH = 0.500 mol H₂SO4 / mol NaOH

b) Actual ratio:

0.360 mol H₂SO4 / 0.203 mol NaOH = 1.77 mol H₂SO₄ / mol NaOH

Since hte actual ratio of H₂SO₄ is greater than the stoichiometric ratio, you conclude that H₂SO₄ is in excess.

5) Amount of H₂SO₄ that reacts:

Since, KOH is the limiting reactant, using 0.203 mol KOH and the stoichiometryc ratio 1 mol H₂SO₄ / 2 mol KOH, you get:

x / 0.203 mol KOH = 1 mol H₂SO₄ / 2 mol KOH ⇒

x = 0.203 / 2 = 0.0677 mol of H₂SO₄

6) Concentration of H₂SO₄ remaining:

Initial amount - amount that reacted = 0.360 mol - 0.0677 mol = 0.292 mol

Total volume = 0.700 liter + 0.750 liter = 1.450 liter

Concetration = M

M = n / V = 0.292 mol / 1.450 liter = 0.201 M ← answer

6 0

3 years ago

Multicellular plants and animals have warden super for specific functions what do eukaryotic cells have to perform specific func

Y_Kistochka [10]

Eukaryota Cells have to Preform: Organelles.

3 0

3 years ago

the chemicals released by burning petroleum in car engines contribute to which local and worldwide effects? Submit

coldgirl [10]

Well air pollution, lung cancer, global warming those are just a couple off if my head

6 0

3 years ago

The temperature in your town is 31°F. The radio announcer says that the temperature will drop 15 degrees. What will the temperat

hoa [83]

Answer:

The temperature of the town will be 15°F.

The equation showing the final temperature after drop say x degrees can be written as:

$T'=(T-x)^oF$

Explanation:

The current temperature in our town = T = 31°F

Temperature drop suggested by radio announcer = 15°

Temperature of the town after temperature drop = T'

$T'=T-15^oF$

$T'=31^oF-15^oF=16^oF$

The equation showing the final temperature after drop say x degrees can be written as:

$T'=(T-x)^oF$

3 0

3 years ago