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VMariaS [17]
3 years ago
8

HNO3 and H2CO3 are examples of ?

Chemistry
1 answer:
Basile [38]3 years ago
7 0
A) acids because they start with h
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Carbons from acetyl CoA are transferred to the citric acid cycle. Which is the first round of the citric acid cycle that could p
Zielflug [23.3K]

Answer:

In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.

Explanation:

In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.

In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.

<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>

<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>

On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.

7 0
3 years ago
Neptune is 30 AU (astronomical units) from the sun. How long, in light minutes, would it take for light from the sun to reach Ne
shtirl [24]

Answer:

250 light minutes takes

Explanation:

1 astonomical unit is equal to 1.50x10¹¹m

The light travels at the speed of 3.0x10⁸m/s. That means in 1 second, travels 3.0x10⁸m. To solve this question we must find the distance of neptune to the sun in meters. In this way we can find the seconds (And minutes) that need the light to travel from the sun to neptune:

<em>Distance from Sun to neptune:</em>

30AU * (1.50x10¹¹m / 1AU) = 4.5x10¹²m

<em>Time transcurred:</em>

4.5x10¹²m * (1s / 3.0x10⁸m) = 15000s

15000s * (1min / 60s) =

<h3>250 light minutes takes</h3>

7 0
3 years ago
An unknown acid solution has PH 3.4. 66% of the acid is ionized. Whats the pka?
juin [17]

Answer:

pKa=3.58

Explanation:

Hello,

In this case, since the pH defines the concentration of hydrogen:

pH=-log([H^+])

[H^+]=10^{-pH}=10^{-3.4}=3.98x10^{-4}

And the percent ionization is:

\% \ ionization=\frac{[H^+]}{[HA]}*100\%

We compute the concentration of the acid, HA:

[HA]=\frac{[H^+]}{\% \ ionization}*100\%=\frac{3.98x10^{-4}}{66\%}  *100\%\\\\

[HA]=6.03x10^{-4}

Thus, the Ka is:

Ka=\frac{[H^+][A^-]}{[HA]}=\frac{3.98x10^{-4}*3.98x10^{-4}}{6.03x10^{-4}}\\  \\Ka=2.63x10^{-4}

So the pKa is:

pKa=-log(Ka)=-log(2.63x10^{-4})\\\\pKa=3.58

Regards.

5 0
3 years ago
Electrons spill in shells in the nucleous the closest shell (n=1) can contain the maximum of. Electrons
stiks02 [169]
The answer is 2 electrons I believe!
8 0
3 years ago
What are “condensation nuclei”?
Kruka [31]

Answer:

Cloud condensation nuclei or CCNs are small particles typically 0.2 µm, or 1/100 the size of a cloud droplet on which water vapor condenses. Water requires a non-gaseous surface to make the transition from a vapour to a liquid; this process is called condensation.

4 0
2 years ago
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