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just olya [345]
3 years ago
8

All of the following can be used to define a base except (3 points) Question 1 options: 1) a hydronium ion donor in a reaction 2

) a substance that increases the concentration of hydroxide ions 3) an electron pair donor in a reaction 4) a substance that is a hydrogen ion acceptor in a reaction
Chemistry
1 answer:
uranmaximum [27]3 years ago
4 0
Answer is: <span>1) a hydronium ion donor in a reaction.
Base is hydroxide ion (OH</span>⁻) donor, not hydronium ion (H₃O⁺).
Lewis base <span>can donate its lone pair of electrons to Lewis acid.
Base </span><span>increases the concentration of hydroxide ions, for example sodium hydroxide or barium hydroxide in water NaOH </span>→ Na⁺ + OH⁻.
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A reaction that absorbs energy
coldgirl [10]

Answer:

Endothermic Reaction

Explanation:

5 0
3 years ago
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Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:
serg [7]

The ground-state electron configurations of Cd^{2+} transition metal ions are diamagnetic [Kr] 4d^{10}. The ion is diamagnetic because there all electrons are paired.

<h3>What is Diamagnetic?</h3>
  • A magnetic field repels diamagnetic materials because it induces an opposing magnetic field in them when it is applied, which produces a repelling force.
  • In contrast, a magnetic field draws paramagnetic and ferromagnetic materials together.
  • All materials experience the quantum mechanical phenomenon known as diamagnetism, which is the only source of magnetism in a material.
  • The magnetic dipoles within paramagnetic and ferromagnetic materials exert an attracting force that outweighs the modest diamagnetic force.
  • Diamagnetic materials have a magnetic permeability that is less than vacuum, or 0.
  • Although superconductors behave as strong diamagnets, diamagnetism is often a modest effect that can only be observed by sophisticated laboratory equipment.

To learn more about Diamagnetic with the given link

brainly.com/question/15462756

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8 0
1 year ago
Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 °C? (HINT: the act
algol13

Answer:

D) 2.3 x 10⁻¹ s⁻¹

Explanation:

The rate constant is related to the activation energy through the formula:

k= Ae^(-Eₐ /RT)

where A is the collision factor, Eₐ the activation energy, R is the gas constant ( 8.314 J/Kmol ) , and T is the temperature (K)

So a plot of lnk versus 1/T ( Arrehenius plot ) gives us a straight line with slope equal -Eₐ/R and intercept lnA

lnk = -(Eₐ/T)(1/T) + lnA

which has the form y= mx + b

In this problem, we can use the data provided to:

a) Using a calculator determine the slope and intercept and then calculate the value of rate constant at 320 ºC, or

b) Plot the data and determine the equation of the best line , and answer the question for k @ 320 ºC by reading the value from the plot.

Once you do the plot, the resulting equation is:

y = - 19 x 10³ x + 30,582 ( R² = 0.999 )

So for T = 320 + 273 K = 593 K

Y = 19 x 10³ X + 30.58

So for T = (320 + 273)K = 593 K

Y =  -19 x 10³ ( 1/593) + 30.58 = -32.04 +30.58 = - 1.46

and then since

y = lnk ⇒ e^y = k

k= e^-1.46 = 2.3 x 10⁻¹ s⁻¹

Note: there is an error of transcription in the value for T = 472.1 ( 1/T = 2.118 x 10⁻³  and  not 2.228 x 10⁻³). You can  recognize this mistake if you plot the data and notice it produces an outlier.

5 0
3 years ago
If i have 4 moles of a gas at a pressure of 5 atm and a volume of 12 liters what is the temperature?
My name is Ann [436]

Answer:

182.70K

Explanation:

Using the general gas equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = 0.0821 Latm/Kmol

T = temperature (K)

Based on the provided information, P = 5 atm, V = 12L, n = 4 moles, T =?

PV = nRT

5 × 12 = 4 × 0.0821 × T

60 = 0.3284T

T = 60/0.3284

T = 182.70K

4 0
3 years ago
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A
Gemiola [76]

Answer:

(0,653±0,002) M of HNO₃

Explanation:

The reaction of standarization of HNO₃ with Na₂CO₃ is:

2 HNO₃ + Na₂CO₃ ⇒ 2 Na⁺ + H₂O + CO₂ + 2NO₃⁻

To obtain molarity of HNO₃ we need to know both moles and volume of this acid. The volume is (27,71±0,05) mL and to calculate the moles it is necessary to obtain the Na₂CO₃ moles and then convert these to HNO₃ moles, thus:

0,9585 g of Na₂CO₃ × ( 1 mole / 105,988 g) =

9,043×10⁻³ mol Na₂CO₃ × ( 2 moles of HNO₃ / 1 mole of Na₂CO₃) = 1,809×10⁻² moles of HNO₃

Molarity is moles divide liters, thus, molarity of HNO₃ is:

1,809×10⁻² moles / 0,02771 L = 0,6527 M of HNO₃

The absolute uncertainty of multiplication is the sum of relative uncertainty, thus:

ΔM = 0,6527M× (0,0007/0,9585 + 0,001/105,988 + 0,05/27,71) =

0,6527 M× 2,54×10⁻³ = 1,7×10⁻³ M

Thus, molarity of HNO₃ solution and its absolute uncertainty is:

(0,653±0,002) M of HNO₃

I hope it helps!

5 0
3 years ago
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