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photoshop1234 [79]
3 years ago
5

The three primary sources of air pollution are _____.

Chemistry
2 answers:
Kisachek [45]3 years ago
7 0

There are four main types of air pollution sources:

<span>mobile sources – such as cars, buses, planes, trucks, and trainsstationary sources – such as power plants, oil refineries, industrial facilities, and factoriesarea sources – such as agricultural areas, cities, and wood burning fireplaces<span>natural sources – such as wind-blown dust, wildfires, and volcanoes........hope i helped</span></span>
ra1l [238]3 years ago
6 0
Cars,air planes,factories
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Which of the following rules should you follow to balance chemical equations?
Firdavs [7]

Answer:

c. add coefficients as needed

Explanation:

A chemical equation is defined as the equation that shows changes in a chemical reaction. A chemical equation consist of reactant and product, reactant is at left side of the arrow and product is at right side of the arrow.

Reactant => Product

While balancing a chemical equation, the basic rule is to balance the coefficient as required. Coefficient represents the number of molecules and is used at front of a chemical symbol. Change in coefficient helps balance the number of atoms or molecules of the substances on both the sides of the arrow.

Subscripts are never allowed to change because it can change the chemical involved in the reaction.

Hence, the correct answer is "c. add coefficients as needed".

3 0
2 years ago
What are 6 types of energies except Potential and Kinetic energy.
aivan3 [116]

Answer:

The different types of energy include thermal energy, radiant energy, chemical energy, nuclear energy, electrical energy, motion energy, sound energy, elastic energy and gravitational energy.

Explanation:

Hope this helps :D

7 0
3 years ago
How many moles of oxide are in 0.050 g of Iron(III) oxide?
makvit [3.9K]

Answer:

0.00031311017345051

7 0
2 years ago
How many grams of carbon dioxide are produced from 0.98 mol of Fe3O4?
nexus9112 [7]
Hello

the answer is 43.129310000000004

Have a nice day
4 0
3 years ago
A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio
-Dominant- [34]

<em>Answer:</em>

  • The concentration of new solution will be 1×10∧-7 M.

<em>Solution:</em>

<em>Data Given </em>

       given mass of fluoxymesterone =16.8mg = 0.0168 g

       molar mass  of fluoxymesterone = 336g/mol

       vol. of fluoxymesterone = 500.0 ml = 0.500 L

      Stock Molarity of  fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

                   Stock Solution :  New Solution

                                 M1.V1 = M2.V2

       ( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

     [( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

     1 × 10∧-7 = M2

<em>Result:</em>

  • The concentration of new solution M2 will be  1 × 10∧-7
3 0
3 years ago
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