Answer:
Explanation:
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
Oxidizing agents:
Oxidizing agents oxidize the other elements and itself gets reduced.
Reducing agents:
Reducing agents reduced the other element are it self gets oxidized.
Consider the following reaction:
2AgCl + Zn  → 2Ag + ZnCl₂
In this reaction oxidation state of Zn on left side is 0 while on right side +2 so it gets oxidized and oxidation state of Ag on left side is +1 and on right side 0 so it get reduced.
4NH₃  +  3O₂   →   2N₂ +  6H₂O
In this reaction oxidation state of nitrogen on left side is -3 while on right side 0 so it gets oxidized and oxidation state of oxygen on left side is 0 and on right side -2 so it get reduced.
Fe₂O₃ +  2Al  →   Al₂O₃ +  2Fe
In this reaction oxidation state of iron on left side is +3 while on right side 0 so it gets reduced and oxidation state of Al on left side is 0 and on right side +3 so it get oxidized.
 
        
             
        
        
        
<span>the table say that at 20 degree celcius 88.0g of NANO3 will remain dissolved in
100 gm of H2O
so at 20 degree celcius 80.0g of H20 will dissolve
(88.0g)x(80g/100g)=70.4g of NANO3
so at 20 degree celcius
86.3g-70.4g= 15.9 gram of NANO3 will come out of solution.</span>
        
             
        
        
        
Answer:
a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b)  ⇒ 16
 ⇒ 16 c) No
 c) No  was not the limiting reactant.
 was not the limiting reactant.
Explanation:
Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.
a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.
b)   ⇒ 16
 ⇒ 16
c)  was not the limiting reactant based on the mol to mol ratio of
 was not the limiting reactant based on the mol to mol ratio of  and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of
 and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of  would also be produced.
 would also be produced.
 
        
             
        
        
        
Answer:
True, in as far as greater magnitude = greater power.