Answer:
1.635 M
Explanation:
Given:
10 mL of 20 volumes Hydrogen Peroxide
Here,
20 volumes of Hydrogen Peroxide means that on decomposition of 1 mL of H₂O₂ 20 mL of O₂ is obtained
also,
means 1 dm³ of H₂O₂ solution produces 20 dm³ oxygen
Now,
at 298K and 1 atm
20 dm³ oxygen = 
moles
or
= 0.817 moles
also,
2H₂O₂ → 2H₂O + O₂
thus,
1 dm³ of solution must contain 2 × moles of O₂ as moles of H₂O₂
thus,
Number of moles of H₂O₂ = 2 × 0.817
or
Number of moles of H₂O₂ = 1.635 moles
Hence,
For 20 volume hydrogen peroxide is 1.635 M
Answer:How many ions are in 2 moles of NaCl?
2 mol NaCl = 2 x 6.02 x 10 23 = 1.204 x 10 24 NaCl formula units 2 mol NaCl = 2 (2 x 6.02 x 10 23 )= 2 (1.204 x 10 24) = 2.408 x 10 24 atoms *2 moles of sodium chloride contains 2.408 x 10 24 ions (combination of Na + ions & Cl – ions). H
Explanation:
sorry i was running out of time
Answer:
3.56x10^24 molecules
Explanation:
The following data were obtained from the question:
Mass of Na2SO4 = 840g
Molar Mass of Na2SO4 = (23 x2) + 32 + (16x4) =46 + 12 + 64 = 142g/mol
From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This also gives that 1mole of Na2SO4 contains 6.02x10^23 molecules.
If 1 mole (i.e 142g) contains 6.02x10^23 molecules,
Therefore, 840g of Na2SO4 will contain = (840 x 6.02x10^23)/142 = 3.56x10^24 molecules
Answer:
the pressure (torr) of theH₂ gas is 736.2 torr
Explanation:
Given that
The H₂ gas produced in a chemical reaction is collected through water in a eudiometer; during this process, the gas collected contains some droplets of water vapor along with these gas.
So; the total pressure in the eudiometer = Pressure in the H₂ gas - Pressure of the water vapor
Where;
= total pressure in the eudiometer = 760.0 torr
= Pressure in the H₂ gas = ???
= Pressure in the water vapor = 23.8 torr
Now:
= +
- = + -
= - +
= (- 23.8 + 760) torr
= 736.2 torr
Thus; the pressure (torr) of theH₂ gas is 736.2 torr
