Answer:
The balanced equation is: H2 (g) +Cl2 (g) →2HCl (g)
Explanation:
Balancing chemical equation refers to balancing the stoichiometric coefficients on the reactants and products side. This must be done as the chemical equation obeys the law of conservation of mass and momentum.
The representation of a chemical reaction in the form of substances is known as a chemical equation. The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation. The Law of conservation of mass governs the balancing of a chemical equation.
Given chemical equation
The balanced chemical equation for the hydrogen + chlorine -> Hydrogen Chloride.
H2 + Cl2 → 2HCl
The equation is balanced as on the reactants side there are two hydrogens present and the same on the products side. For chlorine as well the same thing goes two chlorine atoms on the reactants side and two on the products side.
Answer:
potassium bromide can only conduct electricity when in an aqueous solution due to the electrostatic force between the ionic bonds
Sika have more food choices because they eat both grasses and shrubs, compared to the white-tailed dear who only eats shrubs.
Answer:
Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.
Explanation:
Molarity of HCl solution = 0.1174 M
Volume of HCl solution = 83.15 mL = 0.08315 L
Moles of HCl = n
According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.
Then 0.009762 mol of HCl will recat with:
Moles of Sodium carbonate = 0.004881 mol
Volume of the sodium carbonate containing solution taken = 1L
Concentration of sodium carbonate in the solution before the addition of HCl:
Answer:
Both sulphur and oxygen have two unshared pairs of electrons
Explanation:
The compound sulphur monoxide has the formula S=O. It is quite analogous to the diatomic molecules of the group 16 elements.
We must remember that each group element has six electrons in their outermost shell. Two of these are lone pairs leaving only two electrons available for bond formation.
These two electrons are used to form the sigma and pi bonds in S=O, leaving two lone pairs on each of sulphur and oxygen atoms.