Answer:
1. 0.00352 M
2. 2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)
3. 0.00534 M
Explanation:
1.
Mass of strontium hydroxide= 10.45 g
Volume of solution = 41.00 ml
Number of moles = mass of Sr(OH)2/molar mass of Sr(OH)2 = 10.45g/121.63 g/mol= 0.0859 moles
Molarity= number of moles × volume = 0.0859 ×41/1000 = 0.00352 M
2.
2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)
3.
Concentration of acid CA= the unknown
Volume of acid VA= 31.5 ml
Concentration of base CB= 0.00352 M
Volume of base VB= 23.9 ml
Number of moles of acid NA= 2
Number of moles of base NB= 1
From;
CAVA/CBVB = NA/NB
CAVANB= CBVBNA
CA= CBVBNA/VANB
CA= 0.00352 × 23.9 ×2/31.5 ×1
CA= 0.00534 M
<u>step</u><u> </u><u>by</u><u> </u><u>step</u>
Na(sodium)=2.8.1
Cl (Chlorine)=2.8.7. sodium will give the chlorine the 1 valence electron to become stable ions.
<u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>
<u>p</u><u>o</u><u>t</u><u>t</u><u>a</u><u>s</u><u>i</u><u>u</u><u>m</u><u>. </u><u>(</u><u>2</u><u>.</u><u>8</u><u>.</u><u>8</u><u>.</u><u>1</u><u>)</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>F</u><u>l</u><u>o</u><u>u</u><u>r</u><u>i</u><u>n</u><u>e</u><u>(</u><u>2</u><u>.</u><u>7</u><u>)</u>
<h2>Ionic bonds result from transferring of electrons</h2>
Explanation:
- Ionic bonds result from transferring of electrons.
- An ionic bond is also referred to as an electrovalent bond.
- The main reason for the formation of the bond is an electrostatic attraction between oppositely charged ions that are cation and anion in a chemical compound.
- The formation of such bonds occurs when the valence (outermost) electrons of one atom are transferred to another atom or the loss of electrons from one atom and gain of electrons of another atom.
- The atom that loses the electrons forms cation that is a positively charged ion.
- The atom that gains electrons forms an anion that is a negatively charged ion.
<u>Answer:</u> The percentage abundance of oxygen-16 isotope is 99.76 %
<u>Explanation:</u>
We are given:
Three isotopes of oxygen are there, O-16, O-17 and O-18
Mass of Oxygen-16 isotope = 15.995 amu
Mass of Oxygen-17 isotope = 16.999 amu
Mass of Oxygen-18 isotope = 17.999 amu
Percentage abundance of Oxygen-17 isotope = 0.04 %
Percentage abundance of Oxygen-18 isotope = 0.2 %
We know that:
Percentage abundance of all isotopes together is 100 %
So, Percentage abundance of Oxygen-16 isotope = [100 - (0.04 + 0.2)] = 99.76 %
Hence, the percentage abundance of oxygen-16 isotope is 99.76 %
Answer:
Explanation:To find the number of moles of solute in a volume of a solution, we need to multiply volume by concentration. BUT we also need to check that the units are the same. Molarity (M) is moles per liter, so we need to convert 250mL to L.
250mL=0.250L
Now we can multiply the concentration by volume.
0.4M*0.250L