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OLga [1]
3 years ago
7

Write the full ground-state electron configuration for each: (a) Br (b) Mg (c) Se

Chemistry
1 answer:
fgiga [73]3 years ago
3 0

Answer:

Bromine (35) 1s²2s²2p63s²3p⁶3d¹⁰ 4s² 4p⁵

Magnesium(12) 1s2 2s2 2p6 3s²

Selenium (34) 1s²2s²2p63s²3p⁶3d¹⁰ 4s² 4p4

Explanation:

In the SPDF electronic configuration, the S orbital can accommodate maximum of 2 electrons,

The P orbital has maximum of 6 electrons

The D orbital has maximum of 10 electrons

The F orbital has maximum of 14 electrons

Bromine with atomic number 35 belongs to group seven(7) period four (4) it ground state electron configuration is 1s²2s²2p63s²3p⁶3d¹⁰ 4s² 4p⁵

Magnesium with atomic number 12 belongs to group one, period two(2), it ground state electron configuration is 1s2 2s2 2p6 3s²

Selenium has atomic number of 34, it belongs to group six(6), period four(4) it electronic configuration is 1s²2s²2p63s²3p⁶3d¹⁰ 4s² 4p4

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Answer:

C2H2O4

Explanation:

To get the molecular formula, we first get the empirical formula. This can be done by dividing the percentage compositions by the atomic masses. The percentage compositions are shown as follows :

C = 26.86%

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O = 100 - ( 26.86 + 2.239) = 70.901%

We then proceed to divide by their atomic masses. Atomic mass of carbon is 12 a.m.u , H = 1 a.m.u , O = 16 a.m.u

The division is as follows:

C = 26.86/12 = 2.2383

H = 2.239/1 = 2.239

O = 70.901/16 = 4.4313

We now divide each by the smallest number I.e 2.2383

C = 2.2383/2.2383 = 1

H = 2.239/2.2383 = 1

O = 4.4313/2.2383 = 1.98 = 2

Thus, the empirical formula is CHO2.

To get the molecular formula, we use the molar mass .

(CHO2)n = 90

We add the atomic masses multiplied by n.

(12 + 1 + 2(16))n = 90

45n = 90

n = 90/45 = 2.

Thus , the molecular formula is C2H2O4

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