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igomit [66]
4 years ago
8

LC oscillators have been used in circuits connected to loudspeakers to create some of the sounds of electronic music. What induc

tance must be used with a 6.3 μF capacitor to produce a frequency of 9.8 kHz, which is in the audible range of frequencies?
Physics
1 answer:
Vlad [161]4 years ago
3 0

Answer:

Inductance will be L=13.8581\times 10^3H

Explanation:

We have given capacitance C=6.3\mu F=6.3\times 10^{-6}F

Frequency is given , f=9.8KHz

So angular frequency \omega =2\pi f=2\times 3.14\times 9.8\times 1000=61544rad/sec

For LC circuit we know that angular frequency is given by

\omega =\frac{1}{\sqrt{LC}}

61544 =\frac{1}{\sqrt{LC}}

3.787\times 10^9=\frac{1}{6.3\times 10^{-6}\times L}

L=13.8581\times 10^3H

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4 years ago
Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius
olasank [31]

Answer:

v₂ = 5131.42 m/s

Explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ =  84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

            v = \sqrt{\dfrac{GM}{r}}

     so,

            v \alpha \dfrac{1}{\sqrt{r}}

now,

            \dfrac{v_1}{v_2} =\sqrt{\dfrac{r_2}{r_1}}

            \dfrac{v_2}{4800} =\sqrt{\dfrac{8\times 10^7}{7 \times 10^7}}

                v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s

7 0
3 years ago
You have a resistor of resistance 200 ? and a 6.00-?F capacitor. Suppose you take the resistor and capacitor and make a series c
Ne4ueva [31]

Answer:

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Explanation:

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4 years ago
Convert 9.83 m/s with a radius of 0.85 m to rotations per minute (rpm)
marissa [1.9K]

Answer: Conversion of 9.83 m/s with a radius of 0.85 m into rotations per minute (rpm) is 99.25 m^{-1}.

Explanation:

Given: Speed = 9.83 m/s

Convert m/s into m/minute as follows.

1 min = 60 sec\\9.83 m/s = 9.83 m/s \times \frac{60 s}{1 min}\\= 529.8 m/min

Radius = 0.85 m

Now, rotations take place in circular motion. So, the circumference of a circle is 2 \pi r.

Therefore, circumference is calculated as follows.

Circumference = 2 \times pi \times r\\= 2 \times 3.14 \times 0.85 m\\= 5.338 m

Formula used to calculate rotations per minute (rpm) are as follows.

rpm = \frac{speed (in meter per minute)}{circumference}\\= \frac{529.8 m/min}{5.338 m}\\= 99.25 m^{-1}

Thus, we can conclude that conversion of 9.83 m/s with a radius of 0.85 m into rotations per minute (rpm) is 99.25 m^{-1}.

3 0
3 years ago
During fabrication processes, polymeric materials are generally subjected to which of the following conditions? The ambient temp
geniusboy [140]

Answer:

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Explanation:

In the manufacture of plastic products are used:

Raw material (pellets) which are the monomers that promote the chemical reaction.

To these are added the charges, in order to reduce the cost of the final product and improve some properties. These charges can be fiberglass, paper, metal structures.

Additives are also added whose mission is to improve or achieve certain properties, such as reducing friction, reducing chemical degradation, increasing electrical conductivity, coloring the product, and all this happens in the presence of a catalyst that is responsible for initiating and accelerating the chemical reaction process.

There are different methods of production of plastics, one of the most frequent is by injection.

Injection is a process that is carried out on machines similar to extrusion machines, in which the spindle, in addition to rotating, has an axial displacement.

In the injection, once the mold is filled, it is separated from the nozzle of the machine, breaking the feed channel. After a certain time, the piece already cooled is demoulded.

High pressures and temperatures are necessary, but parts of good finish and at high production speeds are obtained

3 0
4 years ago
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