Ask question

Ask question

All categories

3 years ago

10

The Mid-Atlantic Ocean Ridge is an example of a _____. convergent boundary subduction zone divergent boundary transform boundary

2 answers:

Andre45 [30]3 years ago

8 0

the correct answer is divergent guys i just did it

DIA [1.3K]3 years ago

3 0

<span>If you wanted to know what the mid-atlantic ocean ridge is, you should observe how it behaves. It's divergent because it pushes away the two tectonic plates that were there before. It separated the continents, that is, the Euro-Africa part from the two Americas and pushed them away from each other to where they are.</span>

You might be interested in

what is the average speed of (a) a car that travels 400m in 20s. and (b) an athlete who runs 1500m in 4 minutes

zmey [24]

Answer:

a) 20 m/s

b) 37.5 m)s

Explanation:

Average speed = total distance ÷ total time

=> (a) average speed of a car that travels 400m in 20s

= 400/20 = 20 m/s

& (b) average speed of an athlete who runs 1500m in 4 minutes (or 4×60=240 seconds)

= 1500/240 = 37.5 m/s

5 0

3 years ago

A sound wave has a frequency of 425 Hz. What is the period of this wave?

Serhud [2]

Period is 1/frequency
1/425 = 2.353ms

8 0

3 years ago

What is the electric field at the point x=6.5 m? positive e-fields point to the right.?

Mademuasel [1]

6,5 6,4 6,3 6,2 6
if you know,1

5 0

3 years ago

Set up differential equation of angular S.H.M

3241004551 [841]

Answer:

${ \sf{ \omega \: is \: the \: angular \: velocity}} \\ { \sf{ \theta \: is \: the \: angular \: displacement}}$

3 0

3 years ago

A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the pot

denpristay [2]

Answer:

Part a)

V = 18.16 V

Part b)

$P_r = 345 Watt$

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

$P_r = 345 Watt$

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

$\Delta V = E + i r$

here we have

$E = 12 V$

$i = 56 A$

$r = 0.11$

now we have

$\Delta V = 12 + (0.11)(56) = 18.16 V$

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

Part c)

Rate of energy conversion into EMF is given as

$P_{emf} = i E$

$P_{emf} = (56)(12)$

$P_{emf} = 672 Watt$

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

$V = E - i r$

$V = 12 - (56)(0.11)$

$V = 12 - 6.16 = 5.84 V$

Part e)

now the rate of energy dissipation is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

7 0

3 years ago