Answer:
Displacement after 5 seconds is 155/2 meters
Explanation:
Let X (t) represent the equation of the position, then you have to d2x / dt2 = 5.
Applying the fundamental theorem of the calculation dx/dt = 5t + vo. The speed equation is V (t) = 5t + vo. Since the initial velocity is 30m/s, V (0) = 5 (0) + vo = 30. Therefore, V (t) = dx/dt = 5t + 30. Applying again the fundamental theorem of the calculation X (t) = 5t^2 / 2 + 30t + xo.
Displacement in 5 seconds is given by X (5) - X (0).
X (5) - X (0) = 5 (5)^2/2 +3 (5) + Xo - 5 (0)^2/2 -3 (0) -Xo = 155/2
Displacement after 5 seconds is 155/2 meters
There are two systems that contain only the fundamental frequency and they are the systems C and D.
<h3>What is fundamental frequency?</h3>
The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.
From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.
Learn more about fundamental frequency:brainly.com/question/9424813
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