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Zigmanuir [339]
4 years ago
15

Under what conditions would a rope remain in equilibrium during a tug of war?

Physics
2 answers:
Art [367]4 years ago
8 0

The Answer is B)


jfjfjjjcjfjfjfjfj

Anettt [7]4 years ago
5 0
The best and most correct answer among the choices provided by the question is the second choice. The rope will not be broken until the net force acting on it is not equal to zero anymore. I hope my answer has come to your help. God bless and have a nice day ahead!
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Which is an example of observational learning?
vekshin1
Janice is the one who learned something by watching what was going on in the world around her.
8 0
3 years ago
Read 2 more answers
How does the law of conservation of energy apply to a light bulb? the electrical energy put into the light bulb equals the light
andrew-mc [135]
<span>The law of conservation of energy applies to a light bulb because the energy is being transformed into light and the light bulb is acting as a catalyst. The light bulb itself is not a form of energy, however when in combination with the electrical outlet to the bulb the electricity heats up the metal interior forming it into light. according to the law of conservation energy cannot be created or destroyed, but instead is formed into different kinds of energy. In relation to a light bulb electrical currents are forming heat energy by heating up the metal interior, then the bulb or glass around it allows to radiate light.</span>
7 0
3 years ago
A spacecraft left Earth to collect soil samples from Mars. Which statement is true about the strength of Earth’s gravity on the
ryzh [129]

Answer:

: It Decreases.

As the spacecraft gets farther and farther from Earth, the gravitational  

forces between the spacecraft and the Earth decrease.

Explanation:

5 0
3 years ago
Can someone solve this problem and explain to me how you got it​
evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒F\alpha\frac{q1*q2}{r^{2}}

∴F=k\frac{q1*q2}{r^{2}}

where F is the force of attraction or repulsion

k is Coulumb's constant=9*10^{9}Nm^{2}C^{-2}

q1 and q2 are the magnitude of the charges

r is the distance between two charges

The force between the two charges is attractive if they are of different polarity

The force between the two charges is repulsive if they are of same polarity

Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

F=9*10^{9}*\frac{0.041*0.029}{12^{2}}

F=74312.5N

Question6:

Given: q1=3*10^{-18}C, r=5 m, F=4*10^{-11}N

therefore by Coulumb's law,

4*10^{-11}=9*10^{9}*\frac{3*10^{-18}*q2}{5^{2}}

⇒q2=\frac{4*10^{-11}*25}{9*10^{9}*3*10^{-18}} \\=0.37C

4 0
3 years ago
A 15.0-kg child descends a slide 2.40 m high and reaches the bottom with a speed of 1.10 m/s .
pickupchik [31]

The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

KE = 0.5 * mv^2 =0.5 * 15.0-kg * (1.10 m/s)^2 = 9.1 J

PE = mgh = 15.0-kg * 9.8 m/s^2 *  2.40 m = 352.8 J

The thermal energy is; 352.8 J - 9.1 J = 344J

Learn more about thermal energy due to friction:brainly.com/question/7207509

#SPJ1

7 0
2 years ago
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