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Harlamova29_29 [7]
3 years ago
11

Is telekinesis real??? I really wanna start learning it!

Physics
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

Highly doubt something that requires great focus and mental strength exists

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3 years ago
A cyclist travels 36km in 3 hours. What is the cyclist’s average speed?
dybincka [34]
To determine what the cyclists average speed is, simply divide the distance the cyclist has travelled by the time the cyclist has traveled for.

Assuming that this is the average rate the cyclist is moving at it would be 12 km/hr.
4 0
3 years ago
What characteristics do atoms of carbon-12, carbon-13, and carbon-14 have in common? 1. same number of electrons 2. same number
Rasek [7]

Answer:

The most common of these is carbon 12, 13, 14. All of these isotopes have the same atomic number but different mass numbers. Carbon has the atomic number of 6 which means that all isotopes have the same proton number. However, the number of neutrons is different, thus giving different mass numbers.

7 0
3 years ago
The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde
boyakko [2]

Explanation:

Given data:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Distance d between the plates = 1 mm = 1×10⁻³m

Voltage of the battery is emf = 100 V

Resistance = 1025 ohm

Solution:

In RC circuit, the voltage between the plates is related to time t. Initially the voltage is equal to that of battery V₀ = emf = 100V. But After time t the resistance and capacitor changes it and the final voltage is V that is given by

V = V_{0}(1-e^{\frac{-t}{RC} }  )\\\frac{V}{V_{0} } = 1-e(^{\frac{-t}{RC} })  \\e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }

Taking natural log on both sides,

e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }  \\\frac{-t}{RC} = ln(1-\frac{V}{V_{0} } )\\t = -RCln(1 - \frac{V}{V_{0} })

t = -RC ln (1-\frac{V}{V_{0} })        (1)

Now we can calculate the capacitance by using the area of the plates.

C = ε₀A/d

  = \frac{(8.85*10^{-12))} (20*10^{-4}) }{1*10^{-3} }

  = 18×10⁻¹²F

Now we can get the time when the voltage drop from 100 to 55 V by putting the values of C, V₀, V and R in the equation (1)

t = -RC ln (1-\frac{V}{V_{0} })

 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

5 0
3 years ago
How is energy conserved when a pan of water on an electric stove comes to a boil
Flura [38]

Answer:

Choices?

Explanation:

5 0
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