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Harlamova29_29 [7]
3 years ago
11

Is telekinesis real??? I really wanna start learning it!

Physics
1 answer:
Law Incorporation [45]3 years ago
3 0

Answer:

Highly doubt something that requires great focus and mental strength exists

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if change in blood pressure between the brain and the feet is 1.88×10^4 pa .what will be the volume flow rate from head to feet
klio [65]

Answer: 3765.66 \frac{m^{3}}{s}

Explanation:

We can solve this problem using the <u>Poiseuille equation</u>:

Q=\frac{\pi r^{4}\Delta P}{8\eta L}

Where:

Q  is the Volume flow rate

r=23 cm \frac{1 m}{100 cm}=0.23 m  is the effective radius

L=6 ft \frac{0.3048 m}{1 ft}=1.8288 m  is the length

\Delta P=1.88(10)^{4} Pa  is the difference in pressure

\eta=3(10)^{-3} Pa.s is the viscosity of blood

Solving:

Q=\frac{\pi (0.23 m)^{4}(1.88(10)^{4} Pa)}{8(3(10)^{-3} Pa.s)(1.8288 m)}

Q=3765.66 \frac{m^{3}}{s}

4 0
4 years ago
A spring loaded toy shoots straight upward with a velocity of 4.5 m/s. Determine the maximum height it reaches. Determine the ti
Angelina_Jolie [31]

Recall that

{v_y}^2-{v_{0y}}^2=2a_y(y-y_0)

At its maximum height y_{\mathrm{max}}, the toy will have 0 vertical velocity, so that

-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

\implies y_{\mathrm{max}}=1.0\,\mathrm m

For the toy to reach this maximum height, it takes time t such that

\dfrac{0+v_0}2t=y_{\mathrm{max}}\implies t=0.46\,\mathrm s

which means it takes twice this time, i.e. t=0.92\,\mathrm s, for the toy to reach its original position.

The velocity of the toy when it falls 1.0 m below its starting point is

{v_y}^2-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(0-1.0\,\mathrm m)

\implies{v_y}^2=39.85\,\dfrac{\mathrm m^2}{\mathrm s^2}

\implies v_y=-6.4\,\dfrac{\mathrm m}{\mathrm s}

where we took the negative square root because we expect the toy to be moving in the downward direction.

6 0
3 years ago
The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine
arlik [135]

Answer:

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

U_{A-B}=\bigtriangleup T\\\\F\cos 30°\times h_A - F\sin30°\times h_A + Wh_A=\frac{1}{2}m(v^2_B-v^2_A)\\\\v_B=\sqrt{\frac{2Fh_A(\cos 30° - \sin30°)+mgh_A}{m+v^2_A}}

Here, F is the force acting on the collar, h_A is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, v_B is the velocity of the collar at position B, and v_A is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for h_A, 1.5kg for m, 9.81m/s^2 for g and 0 for v_A

v_B=\sqrt{\frac{2(14.4\times 0.2(\cos 30° - \sin30°)+1.5\times 9.81\times 0.2}{1.5+0}}\\\\=\sqrt{\frac{6.618}{1.5}}\\\\=4.412m/s

Therefore, the velocity at which the collar strikes the end B is 4.412m/s

8 0
3 years ago
A rocket experiences a 45,000 N force as it accelerates at 30 m/s/s. What is the mass of the rocket?
Gre4nikov [31]

Answer:

15,00kg

Explanation:

here's your solution

=> force = 45,000N

=> acceleration = 30m/s^2

=> mass = ?

=> Mass = force/acceleration

=> mass = 45,000/30

=> mass = 15,00kg

hope it helps

6 0
3 years ago
What is the focal length of a lens? the distance between the object and the image distance between the object and the center of
maks197457 [2]
Distance between the focal point and the center of the lens
4 0
3 years ago
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