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2 years ago

What is the molality of a solution containing 15 g NaCl dissolved in 50 g of water

Chemistry

2 answers:

enot [183]2 years ago

7 0

Answer:

cdjkekendnekekekeknenwkwkwkwnrnrnrjejjwjwksnsjnrheifjfuufjeenenej

faltersainse [42]2 years ago

4 0

Hopes this helps:

Answer: 5.132 mol/kg

How I got the answer I looked it up. Please mark as brainlist if it’s right.

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Consider a solution that contains 60.0% r isomer and 40.0% s isomer. if the observed specific rotation of the mixture is –43.0°,

pychu [463]

The solution for this problem is:
Let x denote the specific rotation, R; andLet y denote the specific rotation, S = -x
Solution:60 x - 40 x/100 = - 43
20x = - 4300Divide both sides by 20The answer is:x = - 215 is the specific rotation of the pure r isomer.

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3 years ago

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Triss [41]

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3 years ago

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For the reaction below, complete the rate expression that relates the change in concentration with respect to time to the rate o

Ann [662]

Answer: Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$

Rate in terms of disappearance of $Cl_2$ = $-\frac{1d[Cl_2]}{1dt}$

Rate in terms of appearance of $NOCl$ = $\frac{1d[NOCl]}{2dt}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO+Cl_2\rightarrow 2NOCl$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of = $-\frac{1d[NO]}{2dt}$

Rate in terms of disappearance of = $-\frac{1d[Cl_2]}{1dt}$

Rate in terms of appearance of $NOCl$ = $+\frac{1d[NOCl]}{2dt}$

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3 years ago