What is the molality of a solution containing 15 g NaCl dissolved in 50 g of water
2 answers:
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Answer:
1. D (24.0 moles CO2)
2. A (.239 moles H2)
Explanation:
1. First Balance the equation
1 C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
Then set up a stoiciometric equation so that the moles of O2 cancel out
40mol O2 x = 24.0 moles CO2
2. Set up a stoichiometric equation
10 grams Fe x x
= 0.239 moles H2
Answer:
The energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J
Explanation:
Let the charge on the cation be q₁
Also let the charge on the anion be q₂
A cation q₁ with a valence of 1, has a charge of 1 X 1.602×10⁻¹⁹C = 1.602×10⁻¹⁹C
An anion q₂ with a valence of 3, has a charge of 3 X 1.602×10⁻¹⁹C = 4.806 ×10⁻¹⁹C
The distance between the two charges is 7.5nm = 7.5 X10⁻⁹m
Energy of attraction =
Where k is coulomb's constant = 8.99 X 10⁹ Nm₂/C₂
Energy of attraction =
Energy of attraction = 1.231 X 10⁻¹¹ J
Therefore, the energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J