Answer:
3 is the correct answer i think
Explanation:
Answer:
Molecular Weight Of KAl(SO4)2 12H2O = 475 G / Mol Molecular Weight Of Al = 27 G / Moles.
Explanation:
HOPE THIS HELPS YOU OUT AND IF IT DID PLS MARK ME AS BRAINIEST
The empirical formula : C₁₁O₁₄O₃
<h3>Further explanation</h3>
The assumption of the compound consists of C, H, and O
mass of C in CO₂ =
mass of H in H₂O =
mass of O :
mass sample-(mass C + mass H)
mol of C :
mol of H :
mol of O :
divide by 0.0155(the lowest ratio)
C : H : O ⇒
Explanation:
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2H2 + O2 → 2H2O
First, we will find the moles :
n H2 = m H2 / Mr H2
n H2 = 10 / 2
n H2 = 5 mole
n O2 = m O2 / Mr O2
n O2 = 5 / 16
n O2 = 0.3125 mole
n H2 / coef. H2 > n O2 / coef. O2
So, O2 is the limiting reactant
The mass of water produced :
n H2O = (coef. H2O / coef. O2) • n O2
n H2O = (2/1) • 0.3125
n H2O = 0.625 mole
m H2O = n H2O • Mr H2O
m H2O = 0.625 • 18
m H2O = 11.25 gr
Excesses reactant :
n H2 = 5 - 0.625 = 4.375 mole
m H2 = n H2 • Mr H2
m H2 = 4.375 • 2
m H2 = 8.75 gr
