7(a - 10) = 13 - 2(2a + 3)
7a - 70 = 13 - 4a - 6 = 7 - 4a
7a + 4a = 7 + 70
11a = 77
a = 77/11 = 7
a = 7.
Answer:
Statement 3: DC=CD (Common)
Step-by-step explanation:
According from the statement given, consider ΔADC and ΔBCD, we get
AD=BC(opposite sides of a rectangle are congruent)
∠ADC=∠BCD(angles of a rectangle are 90°)
DC=CD(Common)
Thus, by SAS rule, ΔADC≅ΔBCD and by CPCTC AC=BD.
Thus, Statement 3 that is using the common sides of the triangle jimmy can prove the proof.
Answer:

Step-by-step explanation:
After travelling two hours, the two cruise ships form a triangle. One of the legs of this triangle will be the distance Cruise A travelled, and another will be the distance Cruise B travelled. We can find the distance they travel using:

Cruise A is travelling at 18 miles per hour for 2 hours. Therefore, Cruise A has travelled:

Cruise B is travelling at 15 miles per hour for 2 hours. Therefore, Cruise B has travelled:

Because we are given the angle between these legs, we can use the Law of Cosines to find the third leg. The Law of Cosines is given by:
, where
,
, and
are interchangeable. Let
represent the distance between the two cruises. We have:
(one significant figure).
11 • 55 = 55
The starfish had 55 arms all together.
Hope this helps!