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3 years ago

A cylinder-piston system contains an ideal gas at a pressure of 1.2 x 10° Pa.

Physics

1 answer:

MAVERICK [17]3 years ago

4 0

The change in internal energy of the gas is -9 J

Explanation:

First of all, we need to calculate the amount of work done by the gas. This is given by the equation:

$W=p(V_f - V_i)$

where

$p=1.2\cdot 10^5 Pa$ is the gas pressure

$V_f = 0.0003 m^3$ is the final volume of the gas

$V_i = 0.0006 m^3$ is the initial volume of the gas

Substituting, we find:

$W=(1.2\cdot 10^5)(0.0003-0.0006)=-36 J$

Now we can apply the 1st law of thermodynamics to calculate the change in internal energy of the gas:

$\Delta U = Q - W$

where

$\Delta U$ is the change in internal energy of the gas

Q = -45 J is the heat released by the gas (negative because it is given off bu the system)

W = -36 J is the work done by the gas (negative because it is done by the surrounding on the gas)

Substituting, we find:

$\Delta U = -45 - (-36) = -9 J$

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3 years ago

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Inessa [10]

Answer:

Explanation:

Given the height reached by a balloon after t sec modeled by the equation

h=1/2t²+1/2t

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If h(t)=1/2t²+1/2t

h(40) = 1/2(40)²+1/2 (40)

h(40) = 1600/2 + 40/2

h(40) = 800 + 20

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v = dh/dt

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v(t) = t + 1/2

when v = 0sec

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at v = 30secs

v(30) = 30 + 1/2

v(30) = 30 1/2 ft/sec

average velocity = v(30) - v(0)

average velocity = 30 1/2 - 1/2

average velocity of the balloon between t = 0 and t = 30 = 30 ft/sec

c) Velocity is the change of displacement of a body with respect to time.

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

The velocity of the balloon after 30secs will be;

v(30) = 30+1/2

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The spring constant, k, is a measure of the stiffness of the spring. It is different for different springs and materials.

Calculation for What is the spring constant

First step is to calculate the time period

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