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Mama L [17]
1 year ago
10

using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (c6h6).

the molar mass of benzene is 78.11 g/mol. 2 c6h6(l) 15 o2(g) → 12 co2(g) 6 h2o(g) δh°rxn
Chemistry
1 answer:
aliya0001 [1]1 year ago
4 0

the amount of heat produced from the combustion of 24.3 g benzene (c6h6) is ΔH = -976.5 kJ

There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

Enthalpy, or the value of H, is a unit of measurement for heat that relies on the amount of matter present (number of moles).

Thus, 24.3 g of benzene contains:

n = mass/molar mass, where n = 24.3/78.11, and n = 0.311 moles.

2 moles = 6278 kJ

0.311 moles =x

By the straightforward direct three rule:

2x = -1953.08 x = -976.5 kJ

Learn more about combustion here-

brainly.com/question/15117038

#SPJ4

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A 475 cm3 sample of gas at standard temperature and pressure is allowed to expand until it occupies a
Andrej [43]

The final temperature : 345 K

<h3> Further explanation </h3>

Given

475 cm³ initial volume

600 cm³ final volume

Required

The final temperature

Solution

At standard temperature and pressure , T = 273 K and 1 atm

Charles's Law  :

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

V₁/T₁=V₂/T₂

Input the value :

T₂=(V₂T₁)/V₁

T₂=(600 x 273)/475

T₂=345 K

4 0
3 years ago
Predict: In each "Climate type" box, Highlight the condition you think will lead to the fastest weathering for the given weather
yanalaym [24]

Answer:

Frost Wedging - Hot and dry

Clay Formation - Cold and Wet

Dissolving - Cold, and dry

Explanation:

The frost wedging happen when the climatic condition is hot and dry. The dry weather compensates the heat and the rock wedging happens quickly. For clay formation the weather has to be cold and wet. The cold weather will make the sand indulge with rock particles resulting in the clay formation.

6 0
3 years ago
6.02 kJ&gt;mol. When a small ice cube at -10°C is put into a cup of water at room temperature, which of the following plays a gr
9966 [12]

Answer:

Heat transfer during melting of ice plays greater role in cooling of liquid water.

Explanation:

Temperature of ice = -10 °c

Temperature of water = 0 °c

When ice cube is dipped in to the water.the heat transfer

Q = m c ΔT

⇒ Q = 1 × 2.01 × 10

⇒ Q = 20.1 KJ

Heat transfer during melting of ice Q_{melt} = latent heat of ice

Latent heat of ice = 334 KJ

⇒ Q_{melt} = 334 KJ

Heat transfer during melting of ice is greater value than heat transfer during warming of ice from -10°C to 0°C.

Thus heat transfer during melting of ice plays greater role in cooling of liquid water.

8 0
3 years ago
Can someone solve this for me I'm confused.
Artemon [7]

Answer:

310.53 g of Cu.

Explanation:

The balanced equation for the reaction is given below:

CuSO₄ + Zn —> ZnSO₄ + Cu

Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:

Molar mass of CuSO₄ = 63.5 + 32 + (16×4)

= 63.5 + 32 + 64

= 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of Cu = 63.5 g/mol

Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g

Summary:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.

Thus, 310.53 g of Cu were obtained from the reaction.

6 0
3 years ago
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